Spring Security /找不到j_spring_security_check 404

akc*_*soy 9 spring spring-mvc spring-security thymeleaf

这是我的WebAppInitializer:

@Configuration
public class WebAppInitializer extends AbstractAnnotationConfigDispatcherServletInitializer {

    @Override
    protected Class<?>[] getRootConfigClasses() {
        return new Class<?>[] { AppConfig.class, WebSecurityConfig.class };
    }

    @Override
    protected Class<?>[] getServletConfigClasses() {
        return new Class<?>[] { WebConfig.class };
    }

    @Override
    protected String[] getServletMappings() {
        return new String[] { "/" };
    }
}
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这是我的安全配置:

@Configuration
@EnableWebSecurity
public class WebSecurityConfig extends WebSecurityConfigurerAdapter {

    @Autowired
    private UserDetailsService userDetailsService;

    @Override
    protected void configure(AuthenticationManagerBuilder auth) throws Exception {
        auth.userDetailsService(userDetailsService);
    }

    @Override
    public void configure(WebSecurity web) throws Exception {
        web.ignoring().antMatchers("/resources/**");
    }

    @Override
    protected void configure(HttpSecurity http) throws Exception {
        // @formatter:off
        http.authorizeRequests()
                .antMatchers("/signup", "/about").permitAll()
                .antMatchers("/admin/**").hasRole("ADMIN")
                .anyRequest().authenticated()
                .and().formLogin().loginPage("/login").defaultSuccessUrl("/home").failureUrl("/error").permitAll()
                .and().httpBasic();
        // @formatter:on
    }

}
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这是我的login.html(来自thymeleaf的示例html):

<form th:action="@{/j_spring_security_check}" method="post">
  <label for="j_username">Username</label>:
  <input type="text" id="j_username" name="j_username" /> <br />

  <label for="j_password">Password</label>:
  <input type="password" id="j_password" name="j_password" /> <br />

  <input type="submit" value="Log in" />
</form>
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当我点击登录时,会出现此错误:

HTTP ERROR 404

Problem accessing /j_spring_security_check. Reason:

    Not Found
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我怎样才能摆脱这个错误?我google了很多,但还没有成功.(是的,我不使用任何xml.)

Tan*_*rma 19

如果你使用spring 4.X那么可能是版本问题

a.)login url =/login b.)logout url =/logout

弹簧3.X的情况

a.)login url =/j_spring_security_check b.)logout url =/j_spring_security_logout


akc*_*soy 9

我创建了这个,它现在有效:

import org.springframework.security.web.context.AbstractSecurityWebApplicationInitializer;

public class SecurityWebApplicationInitializer extends AbstractSecurityWebApplicationInitializer {

}
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这会激活SpringSecurityFilterChain.

由于CSRF错误,我还必须从@EnableWebSecurity切换到@EnableWebMvcSecurity.正如在春季文档写的:

...原因是Spring Security正在防范CSRF攻击,并且我们的请求中没有包含CSRF令牌.更新我们的配置以使用@EnableWebMvcSecurity批注,它将与@EnableWebMvcSecurity一样,并提供与Spring MVC的集成.除此之外,当使用Thymleaf 2.1+或Spring MVC标签库时,它将确保我们的CSRF令牌自动包含在我们的表单中...

还要感谢M. Deinum的评论.Spring最近显然将/ j_spring_security_check/j_password/j_username切换为/ login/password/username.