Yii2:在多个where条件的findone()语法

Question

我有一个表ipd_charges列

table - ipd_charges

id    doctor room_category charges_cash charges_cashless
1        1          1              200            300
2        1          2              300            400

表 - patient_admission

id patient_name tpa_name(if not null, equivalent to charges_cashless)
1        1        Null
2        2         1

table daily_ward_entry

id  patient_name  room_name  doctor_name charges ( from ipd charges)
1          1           1           1         200
2          2           2           1         400

我试图使用这个失败的查询:

$model = \app\models\IpdCharges::find()
         ->where(['doctor'=>$id])
         ->andwhere(['room_category'=>$this->room_name])->one();

谢谢.如果需要更多信息,请告诉我.

非常感谢帮助.

Answer 1

请检查以下代码:

$ipdCharges = new IpdCharges();
$ipdCharges->findOne(['doctor' => $id, 'room_category' => $this->room_name]);