我应该如何转换这一个班轮:
curl -d @request.xml -o response.xml http://www.sample.com/soap
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它正在访问请求xml,如下所示:
<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:req="http://sample.com/">
<soap:Body>
<req:getEvents>
<start>2014-12-12T00:00:00+0100</start>
<end>2014-12-13T00:00:00+0100</end>
<type>TYPE</type>
</req:getEvents>
</soap:Body>
</soap:Envelope>
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响应写入response.xml我想直接将响应读入r
had*_*ley 11
这是httr的方法:
library(httr)
r <- POST("http://www.sample.com/soap", body = upload_file("request.xml"))
stop_for_status(r)
content(r)
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