Python-打开文件-readline-列表-转换为字符串

Question

问题/问题详细信息

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我有一个文件（blah.txt），其内容（列表）如下所示：

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Key1 = ['A','B','C','D','E','F','G','H','I','J','K','L' ,'M','N','O','P','Q','R','S','T','U','V','W','X',' Y','Z','']

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在一个简单的 python 文件（称为 CAT.py）内，我执行以下命令：

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infile = open('blah.txt', 'r')\nKey1 = infile.readline()\ninfile.close()\nKey1 = Key1.rstrip('\\n')\nprint(Key1)\n

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Key1 = ['A','B','C','D','E','F','G','H','I','J','K','L' ,'M','N','O','P','Q','R','S','T','U','V','W','X',' Y','Z','']

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print(''.join(Key1))\n

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Key1 = ['A','B','C','D','E','F','G','H','I','J','K','L' ,'M','N','O','P','Q','R','S','T','U','V','W','X',' Y','Z',' '] <---- 这就是我不想要的

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然而\xe2\x80\xa6。

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如果在一个单独的简单 python 文件（称为 DOG.py）中，我在列表上执行以下命令：

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Key1 = ['A','B','C','D','E','F','G','H','I','J','K','L' ,'M','N','O','P','Q','R','S','T','U','V','W','X',' Y','Z','']

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打印（键1）

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['A'、'B'、'C'、'D'、'E'、'F'、'G'、'H'、'I'、'J'、'K'、'L'、' M'、'N'、'O'、'P'、'Q'、'R'、'S'、'T'、'U'、'V'、'W'、'X'、'Y' , 'Z', ' ']

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print(''.join(Key1))

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ABCDEFGHIJKLMNOPQRSTUVWXYZ <---- 这就是我想要的

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问题/问题

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我最终想要看起来像 \xe2\x80\x9cABCDEFGHIJKLMNOPQRSTUVWXYZ\xe2\x80\x9d 的输出，但在我的一生中，我无法弄清楚如何读取文件列表，然后将该列表转换为单个字符串人物。有人可以告诉我哪里出了问题，并向我展示一些可以解决我的问题的代码吗？

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Answer 1

>>> infile = open('blah.txt', 'r')
>>> key1 = infile.readline()
>>> infile.close()
>>> key1 = "Key1 = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z',' ']"
>>> key1 = key1[key1.index('['):key1.index(']')+1]
>>> key1
"['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z',' ']"
>>> ''.join(eval(key1))
'ABCDEFGHIJKLMNOPQRSTUVWXYZ '