Abd*_*ebi 4 c multithreading mutex semaphore ipc
我必须写两个线程.每个人打印5个偶数/奇数从1到100这样(奇数是impair法语,偶数pair).
even 2,4,6,8,10
odd 1,3,5,7,9
even 12,14,16,18,20
odd 13,15,17,19,21
etc...
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我写了这段代码:
#include <stdio.h>
#include <semaphore.h>
#include <pthread.h>
#define maxi 100
pthread_mutex_t mutex;
sem_t p;
sem_t imp;
int tour = 0;
void *pair(void *arg);
void *impair(void *arg);
int main() {
pthread_t tidp, tidimp;
pthread_mutex_init(&mutex, NULL);
sem_init(&p, 0, 1);
sem_init(&imp, 0, 1);
pthread_create(&tidp, NULL, pair, (void *)2);
pthread_create(&tidimp, NULL, impair, (void *)1);
pthread_join(tidp, NULL);
pthread_join(tidp, NULL);
sem_destroy(&imp);
sem_destroy(&p);
pthread_mutex_destroy(&mutex);
return 0;
}
void *pair(void *arg) {
int i = (int)arg;
int j, l;
// sleep(5);
pthread_mutex_lock(&mutex);
if (!tour) {
tour = 1;
pthread_mutex_unlock(&mutex);
sem_wait(&imp);
} else {
pthread_mutex_unlock(&mutex);
}
for (l = 0; l < maxi; l += 10) {
sem_wait(&p);
printf(" Pair ");
pthread_mutex_lock(&mutex);
for (j = 0; j < 10; j += 2) {
printf(" %4d \t", j + i);
}
pthread_mutex_unlock(&mutex);
printf("\n");
sem_post(&imp);
i += 10;
}
pthread_exit(NULL);
}
void *impair(void *arg) {
int i = (int)arg;
int j, l;
pthread_mutex_lock(&mutex);
if (!tour) {
tour = 1;
pthread_mutex_unlock(&mutex);
sem_wait(&p);
} else {
pthread_mutex_unlock(&mutex);
}
for (l = 0; l < maxi; l += 10) {
sem_wait(&imp);
printf("Impair ");
pthread_mutex_lock(&mutex);
for (j = 0; j < 10; j += 2) {
printf(" %4d \t", j + i);
}
pthread_mutex_unlock(&mutex);
printf("\n");
sem_post(&p);
i += 10;
}
pthread_exit(NULL);
}
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我不明白的是,当我运行代码时,有时它会开始odd,有时候是even.更具体地说,当它开始时odd一切正常并且我得到从1到100的所有数字,但是当它开始时even有时我只得到91,有时93,有时97.
谁能告诉我有什么问题?下面的屏幕截图可能有所帮助.

你不是在等两个线程退出:
pthread_join(tidp, NULL);
pthread_join(tidp, NULL);
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其中之一应该是tidimp.