itp*_*sen 7 merge r cross-join data.table
我有一个data.table对象,其中包含多个指定唯一案例的列.在下面的小示例中,变量" name"," job"和" sex"指定唯一ID.我想添加缺失的行,以便每个case都有一行用于另一个变量的每个可能实例," from"(类似于expand.grid).
library(data.table)
set.seed(1)
mydata <- data.table(name = c("john","john","john","john","mary","chris","chris","chris"),
job = c("teacher","teacher","teacher","teacher","police","lawyer","lawyer","doctor"),
sex = c("male","male","male","male","female","female","male","male"),
from = c("NYT","USAT","BG","TIME","USAT","BG","NYT","NYT"),
score = rnorm(8))
setkeyv(mydata, cols=c("name","job","sex"))
mydata[CJ(unique(name, job, sex), unique(from))]
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这是当前的data.table对象:
> mydata
name job sex from score
1: john teacher male NYT -0.6264538
2: john teacher male USAT 0.1836433
3: john teacher male BG -0.8356286
4: john teacher male TIME 1.5952808
5: mary police female USAT 0.3295078
6: chris lawyer female BG -0.8204684
7: chris lawyer male NYT 0.4874291
8: chris doctor male NYT 0.7383247
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这是我想要的结果:
> mydata
name job sex from score
1: john teacher male NYT -0.6264538
2: john teacher male USAT 0.1836433
3: john teacher male BG -0.8356286
4: john teacher male TIME 1.5952808
5: mary police female NYT NA
6: mary police female USAT 0.3295078
7: mary police female BG NA
8: mary police female TIME NA
9: chris lawyer female NYT -NA
10: chris lawyer female USAT -NA
11: chris lawyer female BG -0.8204684
12: chris lawyer female TIME -NA
13: chris lawyer male NYT 0.4874291
14: chris lawyer male USAT NA
15: chris lawyer male BG NA
16: chris lawyer male TIME NA
17: chris doctor male NYT 0.7383247
18: chris doctor male USAT NA
19: chris doctor male BG NA
20: chris doctor male TIME NA
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这是我尝试过的:
setkeyv(mydata, cols=c("name","job","sex"))
mydata[CJ(unique(name, job, sex), unique(from))]
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但是我收到以下错误并添加fromLast = TRUE(或FALSE)并没有给我正确的解决方案:
Error in unique.default(name, job, sex) :
'fromLast' must be TRUE or FALSE
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以下是我遇到的相关答案(但似乎没有处理多个键控列): 向数据表添加缺失的行
这里有几种可能性 - https://github.com/Rdatatable/data.table/pull/814
CJ.dt = function(...) {
rows = do.call(CJ, lapply(list(...), function(x) if(is.data.frame(x)) seq_len(nrow(x)) else seq_along(x)));
do.call(data.table, Map(function(x, y) x[y], list(...), rows))
}
setkey(mydata, name, job, sex, from)
mydata[CJ.dt(unique(data.table(name, job, sex)), unique(from))]
# name job sex from score
# 1: chris doctor male NYT 0.7383247
# 2: chris doctor male BG NA
# 3: chris doctor male TIME NA
# 4: chris doctor male USAT NA
# 5: chris lawyer female NYT NA
# 6: chris lawyer female BG -0.8204684
# 7: chris lawyer female TIME NA
# 8: chris lawyer female USAT NA
# 9: chris lawyer male NYT 0.4874291
#10: chris lawyer male BG NA
#11: chris lawyer male TIME NA
#12: chris lawyer male USAT NA
#13: john teacher male NYT -0.6264538
#14: john teacher male BG -0.8356286
#15: john teacher male TIME 1.5952808
#16: john teacher male USAT 0.1836433
#17: mary police female NYT NA
#18: mary police female BG NA
#19: mary police female TIME NA
#20: mary police female USAT 0.3295078
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