Luc*_*man 4 python werkzeug flask
我做了一个简单的烧瓶应用:
Trying 127.0.0.1...
Connected to localhost.
Escape character is '^]'.
GET / HTTP/1.1
host:google.be
HTTP/1.0 404 NOT FOUND
Content-Type: text/html
Content-Length: 233
Server: Werkzeug/0.9.6 Python/2.7.6
Date: Mon, 08 Dec 2014 19:15:43 GMT
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 3.2 Final//EN">
<title>404 Not Found</title>
<h1>Not Found</h1>
<p>The requested URL was not found on the server. If you entered the URL manually please check your spelling and try again.</p>
Connection closed by foreign host.
我希望改变的一件事是服务器标题,此刻被设置为Werkzeug/0.9.6 Python/2.7.6我自己的选择.但我似乎无法在文档中找到有关如何执行此操作的任何内容.
您可以使用Flask的make_response方法添加或修改标头.
from flask import make_response
@app.route('/index')
def index():
resp = make_response("Hello, World!")
resp.headers['server'] = 'ASD'
return resp
小智 6
@bcarroll的答案有效，但是它将绕过原始process_response方法中定义的其他进程，例如设置会话cookie。为避免上述情况：
class localFlask(Flask):
def process_response(self, response):
#Every response will be processed here first
response.headers['server'] = SERVER_NAME
super(localFlask, self).process_response(response)
return(response)
您可以通过覆盖 Flask.process_response() 方法来更改每个响应的服务器标头。
from flask import Flask
from flask import Response
SERVER_NAME = 'Custom Flask Web Server v0.1.0'
class localFlask(Flask):
def process_response(self, response):
#Every response will be processed here first
response.headers['server'] = SERVER_NAME
return(response)
app = localFlask(__name__)
@app.route('/')
def index():
return('<h2>INDEX</h2>')
@app.route('/test')
def test():
return('<h2>This is a test</h2>')
http://flask.pocoo.org/docs/0.12/api/#flask.Flask.process_response