jak*_*kob 5 javascript php jquery json jquery-select2
我正在使用Select2 jquery插件,我无法使用json获得结果.在浏览器中查看json响应时看起来没问题.像这样例如:
[{
"id" : "50",
"family" : "Portulacaceae "
}, {
"id" : "76",
"family" : "Styracaceae "
}, {
"id" : "137",
"family" : "Dipsacaceae"
}
]
在这种情况下使用ajax调用的URL是:http://localhost/webpage/json_family.php?term=acac&_=1417999511783但是我无法在select2输入中得到结果,控制台说:
未捕获的TypeError:无法读取未定义的属性"长度"
这是代码:
html
<input type="hidden" id="select2_family" name="term" style="width:30%" />
JS
$("#select2_family").select2({
minimumInputLength: 3,
ajax: {
url: "json_family.php",
dataType: 'json',
data: function (term) {
return {
term: term,
};
},
results: function (data) {
return { results: data.results };
}
}
});
PHP
$myArray = array();
if ($result = $mysqli->query("SELECT id,family FROM family WHERE family LIKE '%$term%'")) {
$tempArray = array();
while($row = $result->fetch_object()) {
$tempArray = $row;
array_push($myArray, $tempArray);
}
echo json_encode($myArray);
}
代码中是否有错误？
好的,我的示例在我的测试服务器上工作,请执行以下操作
将您的查询更改为此,更改了一些名称以便于阅读,但应该是相同的功能,重要的部分是在查询中添加"AS TEXT"
$query = $mysqli->query("SELECT id, family AS text FROM family WHERE family LIKE '%$term%'"));
while ($row = mysql_fetch_assoc($query)) {
$return[] = $row;
}
echo json_encode($return);
第二,看起来你试图从名为"结果"的json响应中调用一个属性
如果是这种情况你的json应该是这样的,请注意由于上面的更改,系列现在是文本:
{
"results":
[
{
"id": "50",
"text": "Portulacaceae "
},
{
"id": "76",
"text": "Styracaceae "
},
{
"id": "137",
"text": "Dipsacaceae"
}
]
}
但是您的php不会创建属性结果,因此请更改结果函数以删除.results属性调用
results: function (data) {
return { results: data };
}
我使用的最终代码(注意我没有逃避/清理$ _GET [term]或将其绑定到查询,建议你这样做)如果你仍然有问题我可以发送一个链接到我的网站示例
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="//cdnjs.cloudflare.com/ajax/libs/select2/3.5.2/select2.css">
<script type="text/javascript" src="//cdnjs.cloudflare.com/ajax/libs/jquery/2.1.1/jquery.js"></script>
<script type="text/javascript" src="//cdnjs.cloudflare.com/ajax/libs/select2/3.5.2/select2.js"></script>
</head>
<script>
$(document).ready(function () {
$("#select2_family").select2({
minimumInputLength: 3,
ajax: {
url: "select2.php",
dataType: 'json',
data: function (term) {
return {
term: term,
};
},
results: function (data) {
return { results: data };
}
}
});
});
</script>
<input type="hidden" id="select2_family" name="term" style="width:30%" />
</html>
PHP
<?
/*** connection strings ***/
// get the database singleton instance
$yog = MySqlDatabase::getInstance();
// connect
try {
$yog->connect($host, $user, $password, $db_name);
}
catch (Exception $e) {
die($e->getMessage());
}
$term = $_GET['term'];
if (!$term){
$sub = $yog->query("SELECT id, family AS text FROM family");
} else {
$sub = $yog->query("SELECT id, family AS text FROM family where family like '%$term%'");
}
while ($row = mysql_fetch_assoc($sub)) {
$return[] = $row;
}
echo json_encode($return);
?>