IF-THEN语句SAS中的多个条件/变量

Mik*_*e L 1 if-statement sas

我有一个数据集,它有两个变量,我正在尝试创建新的组.第一个变量是"religiosity",第二个变量是"Av_Anti",两者都是数字变量.我正在尝试创建组,分成9组,低/中/高宗教信仰和低/中/高Av_Anti.

DATA LYING1;
SET LYING;
    IF RELIGIOSITY = (1 OR 2) AND Av_anti <=3 THEN Rel_Anti = "LowR,LowA";
    IF RELIGIOSITY = (1 OR 2) AND Av_anti (>3 AND <=7) THEN Rel_Anti = "LowR,MidA";
    IF RELIGIOSITY = (1 OR 2) AND Av_anti >7 THEN Rel_Anti = "LowR,HighA";
    IF RELIGIOSITY = (3 OR 4 OR 5) AND Av_anti <=3 THEN Rel_Anti = "MidR,LowA";
    IF RELIGIOSITY = (3 OR 4 OR 5) AND Av_anti (>3 AND <=7) THEN Rel_Anti = "MidR,MidA";
    IF RELIGIOSITY = (3 OR 4 OR 5) AND Av_anti >7 THEN Rel_Anti = "MidR,HighA";
    IF RELIGIOSITY = (6 OR 7) AND Av_anti <=3 THEN Rel_Anti = "HighR,LowA";
    IF RELIGIOSITY = (6 OR 7) AND Av_anti (>3 AND <=7) THEN Rel_Anti = "HighR,MidA";
    IF RELIGIOSITY = (6 OR 7) AND Av_anti >7 THEN Rel_Anti = "HighR,HighA";
    ELSE Rel_Anti = "Error";
RUN;
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我一直在收到消息

  "The function AV_ANTI is unknown, or cannot be accessed." 
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问题是,我检查了那个变量,它拼写正确并且在被调用的数据集中列出了它.我不知道为什么SAS不会将其视为变量?我似乎也遇到了逻辑运算符的一些问题(>,<=).我错过了什么吗?

Ree*_*eza 8

您的比较/范围中包含无效的SAS语法.您应该使用IN运算符检查是否包含在值列表中,然后将每个变量与每个比较的边界进行比较.(即不是:

Av_anti (>3 AND <=7) 
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但:

Av_anti>3 and Av_anti<=7
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要么 :

3<AV_atni<=7
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以下应该有效.我还认为如果不是全部,我打算有其他的,否则你的最后一个条件将全部设置为Error或LowR/MidA.

DATA LYING1;
SET LYING;
    IF RELIGIOSITY in (1, 2) AND Av_anti <=3 THEN Rel_Anti = "LowR,LowA";
    ELSE IF RELIGIOSITY in  (1, 2) AND (Av_anti >3 AND AV_anti<=7) THEN Rel_Anti = "LowR,MidA";
    ...
    ELSE Rel_Anti = "Error";
RUN;
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更好的解决方案可能是:

Data lying1;
    set lying;
    IF RELIGIOSITY in (1, 2) then P1='LowR';
    else IF RELIGIOSITY in (3, 4, 5) then P1='MidR';
    else IF RELIGIOSITY in (6,7) then P1='HighR';
    else P1='Error';

    if av_anti<=3 then P2='LowA';
    else if  3<av_anti<=7 then P2='MidA';
    else if AV_Anti>7 then 'HighA';
    else P2='Error';

    Rel_Anti=catx(",", P1, P2);
run;
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