在一个sql查询中选择最大值和最小值

Pro*_*kie 2 php mysql sql stored-procedures

我有一个表有记录及其时间戳.现在我需要获得最早的记录和最新的记录

9/10/2014 6:54
9/10/2014 6:53
9/10/2014 6:51
9/8/2014 8:09
9/8/2014 7:00
9/5/2014 7:38
9/5/2014 3:57
9/5/2014 3:51
9/4/2014 11:09
9/4/2014 8:39
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目前这是我通过发送两个数据库调用来减少下行处理的方式

$new_timestamp = mysql_query("SELECT TIMESTAMP FROM $rectable ORDER BY TIMESTAMP DESC LIMIT 1");
$col_old = mysql_fetch_assoc($new_timestamp);
$old = $col_new['TIMESTAMP'];

$new_timestamp1 = mysql_query("SELECT TIMESTAMP FROM $rectable ORDER BY TIMESTAMP ASC LIMIT 1");
$col_new = mysql_fetch_assoc($new_timestamp1);
$new = $col_new['TIMESTAMP'];
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是否有任何方法可以优化此代码和fullfiill要求,而无需发送两个数据库调用,通过特殊查询或存储的进程

Fuz*_*ree 5

您可以使用maxmin获取最新和最旧的时间戳

select max(timestamp), min(timestamp) from mytable
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