Scala中2套的交叉产品

Question

val cross = (for (x<-setA; y<-setB) yield (x,y))

val cross2 = (setA flatMap (x => setB map ((x,_)))

有没有更优雅的方式来与跨产品运营商,或一些这样的？例如:

val cross3 = setA cross setB

Answer 1

import scala.collection.Set

class
Crossable[E1](es1: Traversable[E1])
{
    def
    ×[E2](es2: Traversable[E2]): Traversable[(E1, E2)] =
      for (e1 <- es1; e2 <- es2) yield (e1, e2)

    def
    cross[E2](es2: Traversable[E2]): Traversable[(E1, E2)] =
      for (e1 <- es1; e2 <- es2) yield (e1, e2)
}


object
Crossable
{
    implicit
    def
    trav2Crossable[E1](es1: Traversable[E1]): Crossable[E1] =
        new Crossable[E1](es1)
}


object
CrossableTest
{
    def
    main(args: Array[String]): Unit = {
        import Crossable.trav2Crossable

        val es1 = Set(1, 2, 3)
        val es2 = List("a", "b", "c")

        (es1 × es2) foreach(printf("  %s%n", _))
    }
}

% scala -cp . CrossableTest
  (1,c)
  (2,b)
  (3,a)
  (2,a)
  (1,a)
  (3,b)
  (3,c)
  (1,b)
  (2,c)