检查Type实例是否是C#中可为空的枚举

Question

我如何检查Type是否是C#中可以为空的枚举

Type t = GetMyType();
bool isEnum = t.IsEnum; //Type member
bool isNullableEnum = t.IsNullableEnum(); How to implement this extension method?

Answer 1

public static bool IsNullableEnum(this Type t)
{
    Type u = Nullable.GetUnderlyingType(t);
    return (u != null) && u.IsEnum;
}

Answer 2

编辑:我将把这个答案留下来,因为它会起作用,它会演示一些读者可能不知道的电话.然而,卢克的答案肯定更好 - 去投票吧:)

你可以做:

public static bool IsNullableEnum(this Type t)
{
    return t.IsGenericType &&
           t.GetGenericTypeDefinition() == typeof(Nullable<>) &&
           t.GetGenericArguments()[0].IsEnum;
}

Answer 3

从C#6.0开始,接受的答案可以重构为

Nullable.GetUnderlyingType(t)?.IsEnum == true

转换bool需要== true吗？布尔