在haskell中使用ord函数不是范围

Question

很简单,我想使用该函数将字符转换为整数ord,但是它不会自动加载到前奏中,因为它说:

*Main> ord 'a'

<interactive>:55:1:
Not in scope: ‘ord’
Perhaps you meant one of these:
  ‘odd’ (imported from Prelude), ‘or’ (imported from Prelude)

为了天堂的缘故,我怎么能用它？

Answer 1

您需要先导入Data.Char:

import Data.Char