C中的整数获取随机值

Question

我想通过bluez API在C中编写程序

我使用这个网站进行教程:

这是我的代码:

#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <sys/socket.h>
#include <bluetooth/bluetooth.h>
#include <bluetooth/hci.h>
#include <bluetooth/hci_lib.h>


int main(int argc, char **argv)
{
    int dev_id = hci_get_route(NULL);
    int res_scan=NULL;
    int count;
    inquiry_info *device_info=NULL;
    res_scan = hci_inquiry(dev_id,3,255,NULL,&device_info,IREQ_CACHE_FLUSH);
    printf("%i\n",res_scan);
    for(count = 0;count < res_scan;count++)
    {
        char *name;
        printf("count Before : %i\n",count);
        ba2str(&(device_info+count)->bdaddr,&name);
        printf("count After : %i\n",count);

        printf("%s\n",&name);
    }



}

和控制台:

2
count Before : 0
count After : 1111833143
00:17:EB:5D:1B:86

为什么count值后ba2str(&(device_info+count)->bdaddr,&name);获得随机值？

在该来源我链接这个问题不会发生!？

Answer 1

代替

char *name;
...
printf("%s\n",&name);

使用

char name[248] = { 0 };
...
printf("%s\n",name);