Ron*_*nin 84 json curl node.js express node-request
我正在尝试使用nodejs和请求 [2] 向谷歌QPX Express API [1]发出HTTP POST请求.
我的代码如下:
// create http request client to consume the QPX API
var request = require("request")
// JSON to be passed to the QPX Express API
var requestData = {
"request": {
"slice": [
{
"origin": "ZRH",
"destination": "DUS",
"date": "2014-12-02"
}
],
"passengers": {
"adultCount": 1,
"infantInLapCount": 0,
"infantInSeatCount": 0,
"childCount": 0,
"seniorCount": 0
},
"solutions": 2,
"refundable": false
}
}
// QPX REST API URL (I censored my api key)
url = "https://www.googleapis.com/qpxExpress/v1/trips/search?key=myApiKey"
// fire request
request({
url: url,
json: true,
multipart: {
chunked: false,
data: [
{
'content-type': 'application/json',
body: requestData
}
]
}
}, function (error, response, body) {
if (!error && response.statusCode === 200) {
console.log(body)
}
else {
console.log("error: " + error)
console.log("response.statusCode: " + response.statusCode)
console.log("response.statusText: " + response.statusText)
}
})
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我想要做的是使用multipart参数传递JSON [3].但是没有正确的JSON响应,我得到了一个错误(400未定义).
当我使用相同的JSON和API Key使用CURL发出请求时,它工作正常.所以我的API密钥或JSON没有任何问题.
我的代码出了什么问题?
编辑:
工作CURL示例:
i)我将我传递给我的请求的JSON保存到名为"request.json"的文件中:
{
"request": {
"slice": [
{
"origin": "ZRH",
"destination": "DUS",
"date": "2014-12-02"
}
],
"passengers": {
"adultCount": 1,
"infantInLapCount": 0,
"infantInSeatCount": 0,
"childCount": 0,
"seniorCount": 0
},
"solutions": 20,
"refundable": false
}
}
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ii)然后,在终端我切换到新创建的request.json文件所在的目录并运行(myApiKey显然代表我的实际API密钥):
curl -d @request.json --header "Content-Type: application/json" https://www.googleapis.com/qpxExpress/v1/trips/search?key=myApiKey
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[1] https://developers.google.com/qpx-express/ [2]为nodejs设计的http请求客户端:https://www.npmjs.org/package/request [3]这里是我发现的一个例子https://www.npmjs.org/package/request#multipart-related [4] QPX Express API返回400解析错误
Tob*_*obi 164
我认为以下应该有效:
// fire request
request({
url: url,
method: "POST",
json: requestData
}, ...
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在这种情况下,Content-type: application/json
标题会自动添加.
Dan*_*ker 18
我在这方面工作了太久.帮助我的答案是: 发送带有node.js的Content-Type:application/json post
其中使用以下格式:
request({
url: url,
method: "POST",
headers: {
"content-type": "application/json",
},
json: requestData
// body: JSON.stringify(requestData)
}, function (error, resp, body) { ...
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msc*_*dex 10
您不需要multipart,而是需要"普通"POST请求(with Content-Type: application/json
).这就是你所需要的:
var request = require('request');
var requestData = {
request: {
slice: [
{
origin: "ZRH",
destination: "DUS",
date: "2014-12-02"
}
],
passengers: {
adultCount: 1,
infantInLapCount: 0,
infantInSeatCount: 0,
childCount: 0,
seniorCount: 0
},
solutions: 2,
refundable: false
}
};
request('https://www.googleapis.com/qpxExpress/v1/trips/search?key=myApiKey',
{ json: true, body: requestData },
function(err, res, body) {
// `body` is a js object if request was successful
});
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现在有了新的JavaScript版本(ECMAScript 6 http://es6-features.org/#ClassDefinition),有一种更好的方法来使用nodejs和Promise请求提交请求(http://www.wintellect.com/devcenter/nstieglitz/5 -reat-features-in-es6-harmony)
使用库:https: //github.com/request/request-promise
npm install --save request
npm install --save request-promise
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客户:
//Sequential execution for node.js using ES6 ECMAScript
var rp = require('request-promise');
rp({
method: 'POST',
uri: 'http://localhost:3000/',
body: {
val1 : 1,
val2 : 2
},
json: true // Automatically stringifies the body to JSON
}).then(function (parsedBody) {
console.log(parsedBody);
// POST succeeded...
})
.catch(function (err) {
console.log(parsedBody);
// POST failed...
});
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服务器:
var express = require('express')
, bodyParser = require('body-parser');
var app = express();
app.use(bodyParser.json());
app.post('/', function(request, response){
console.log(request.body); // your JSON
var jsonRequest = request.body;
var jsonResponse = {};
jsonResponse.result = jsonRequest.val1 + jsonRequest.val2;
response.send(jsonResponse);
});
app.listen(3000);
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