C++:如何生成Pascal三角形的"第n"行？

Question

这是我的代码:

#include <iostream>
using namespace std;

int main()
{
    int n,k,i,x;
    cout << "Enter a row number for Pascal's Triangle: ";
    cin >> n; 
    for(i=0;i<=n;i++)
    {
        x=1;
        for(k=0;k<=i;k++)
        {
            cout << x << '\t';
            x = x * (i - k) / (k + 1);
        }
    cout << endl;
    }
    return 0;
}

如何更改它以便它只显示第n行而不是整个三角形？TIA.

Answer 1

只需删除外循环:

int main()
{
    cout << "Enter a row number for Pascal's Triangle: ";
    cin >> n; 
    int x = 1;
    for (int k = 0; k <= n; k++)
    {
        cout << x << '\t';
        x = x * (n - k) / (k + 1);
    }
    cout << endl;
    return 0;
}