JPA 2.1实体图表返回重复的结果

Question

我开始在JPA 2.1中使用新的实体图形功能来指定必须加载的Lazy集合.考虑以下课程:

@Entity
@NamedQueries({
    @NamedQuery(name="findWithFilterAttr","select a from A a where a.filterAttribute like :filter")
})
@NamedEntityGraphs({
@NamedEntityGraph(name = "graph.childs", attributeNodes = @NamedAttributeNode("childs"))})
public class A{
  @Id
  private long id;
  @OneToMany(mappedBy="parent")
  private List<B> childs;
  private String filterAttribute;
}
@Entity
public class B{ 
  @Id
  private long id;
  @ManyToOne
  private A parent;
}

当我执行命名查询以获取具有实体图形提示的A实体列表时,我得到一个带有重复A实体的集合.如何只加载A实体一次.

我正在使用:

• Hibernate 4.3.5
• Wildfly 8.1

Answer 1

我终于解决了这个问题,我将DISTINCT添加到命名查询中,现在一切正常....导致错误,因为当JPA Provider找到实体图形提示时,它会创建一个带子表的LEFT JOIN.没有实体图的原始查询:

11:55:28,950 INFO  [stdout] (default task-23) Hibernate: 
11:55:28,950 INFO  [stdout] (default task-23)     select
11:55:28,951 INFO  [stdout] (default task-23)         entitya0_.id as id1_0_0_,
11:55:28,951 INFO  [stdout] (default task-23)         childs1_.id as id1_1_1_,
11:55:28,951 INFO  [stdout] (default task-23)         entitya0_.filter as filter2_0_0_,
11:55:28,951 INFO  [stdout] (default task-23)         childs1_.parent_id as parent_i2_1_1_,
11:55:28,951 INFO  [stdout] (default task-23)         childs1_.parent_id as parent_i2_0_0__,
11:55:28,951 INFO  [stdout] (default task-23)         childs1_.id as id1_1_0__ 
11:55:28,951 INFO  [stdout] (default task-23)     from
11:55:28,951 INFO  [stdout] (default task-23)         EntityA entitya0_ 
11:55:28,951 INFO  [stdout] (default task-23)     left outer join
11:55:28,952 INFO  [stdout] (default task-23)         EntityB childs1_ 
11:55:28,952 INFO  [stdout] (default task-23)             on entitya0_.id=childs1_.parent_id 
11:55:28,952 INFO  [stdout] (default task-23)     where
11:55:28,952 INFO  [stdout] (default task-23)         entitya0_.filter like ?

使用distinct和entity graph查询:

11:57:25,051 INFO  [stdout] (default task-24) Hibernate: 
11:57:25,052 INFO  [stdout] (default task-24)     select
11:57:25,052 INFO  [stdout] (default task-24)         distinct entitya0_.id as id1_0_0_,
11:57:25,052 INFO  [stdout] (default task-24)         childs1_.id as id1_1_1_,
11:57:25,052 INFO  [stdout] (default task-24)         entitya0_.filter as filter2_0_0_,
11:57:25,052 INFO  [stdout] (default task-24)         childs1_.parent_id as parent_i2_1_1_,
11:57:25,052 INFO  [stdout] (default task-24)         childs1_.parent_id as parent_i2_0_0__,
11:57:25,052 INFO  [stdout] (default task-24)         childs1_.id as id1_1_0__ 
11:57:25,052 INFO  [stdout] (default task-24)     from
11:57:25,052 INFO  [stdout] (default task-24)         EntityA entitya0_ 
11:57:25,052 INFO  [stdout] (default task-24)     left outer join
11:57:25,052 INFO  [stdout] (default task-24)         EntityB childs1_ 
11:57:25,052 INFO  [stdout] (default task-24)             on entitya0_.id=childs1_.parent_id 
11:57:25,052 INFO  [stdout] (default task-24)     where
11:57:25,052 INFO  [stdout] (default task-24)         entitya0_.filter like ?