如果我理解正确的话.你可以这样做:
SELECT
client,
thickness,
material,
SUM(amount) AS TotalAmount
FROM
Table1
GROUP BY
client,
thickness,
material
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
883 次 |
| 最近记录: |