将2个参数传递给Laravel路径 - 资源

Question

我正在尝试使用资源构建我的路由,以便我可以将两个参数传递到我的资源中.

我将举几个URLS的外观示例:

domain.com/dashboard
domain.com/projects
domain.com/project/100
domain.com/project/100/emails
domain.com/project/100/email/3210
domain.com/project/100/files
domain.com/project/100/file/56968

所以你可以看到我总是需要引用project_id以及电子邮件/文件ID等.

我意识到我可以通过手动编写所有路径来手动执行此操作,但我正在尝试坚持资源模型.

我觉得这样的事可能有用吗？

Route::group(['prefix' => 'project'], function(){
  Route::group(['prefix' => '{project_id}'], function($project_id){

    // Files
    Route::resource('files', 'FileController');

  });
});

Answer 1

据我所知,资源

Route::resource('files', 'FileController');

上面提到的资源将路由以下网址.

您的资源控制器处理的几个操作 Route::resource('files', 'FileController');

Route::get('files',FileController@index) // get req will be routed to the index() function in your controller
Route::get('files/{val}',FileController@show) // get req with val will be routed to the show() function in your controller
Route::post('files',FileController@store) // post req will be routed to the store() function in your controller
Route::put('files/{id}',FileController@update) // put req with id will be routed to the update() function in your controller
Route::delete('files',FileController@destroy) // delete req will be routed to the destroy() function in your controller

resource上面提到的单一内容将完成所有列出的内容routing

除了那些你必须写你的 custom route

在您的场景中

Route::group(['prefix' => 'project'], function(){
  Route::group(['prefix' => '{project_id}'], function($project_id){

    // Files
    Route::resource('files', 'FileController');

  });
}); 

domain.com/project/100/files

如果get请求将路由到FileController@index
其post请求将被路由到的请求FileController@store

如果您的" domain.com/project/100/file/56968"更改为" domain.com/project/100/files/56968" (文件到文件),则会发生以下生根...

domain.com/project/100/files/56968

如果get请求将被路由到FileController@show
其put请求将被路由到FileController@update
其delete请求将被路由到的请求FileController@destroy

它对url你提到的任何其他内容都没有影响

提供,您需要具有RESTful资源控制器

Answer 2

对于像'/ project/100/file/56968'这样的请求,您必须像这样指定您的路线:

Route::resource('project.file', 'FileController');

然后你可以在控制器的show方法中获取参数:

public function show($project, $file) {
    dd([
        '$project' => $project,
        '$file' => $file
    ]);
}

这个例子的结果将是:

array:2 [?
  "$project" => "100"
  "$file" => "56968"
]