MongoTemplate pull subdocument

Question

我需要在MongoTemplate中拉一个子文档,但无法弄清楚如何做到这一点.

我保存的文件是:

{
    "_id" : "FooUser",
    "_class" : "com.domain.User",
    "tests" : [ 
        {
            "variant" : {
                "_id" : "C",
                "probability" : "0.5"
            },
            "experiment" : {
                "$ref" : "experiment",
                "$id" : "MyExperiment2"
            }
        }, 
        {
            "variant" : {
                "_id" : "B",
                "probability" : "0.5"
            },
            "experiment" : {
                "$ref" : "experiment",
                "$id" : "MyExperiment1"
            }
        }
    ]
}

我只需要删除具有MyExperiment1的测试.执行以下命令有效:

db.user.update( {}, {$pull: { "tests":{"experiment.$id":"MyExperiment1"}}}, {multi: true} )

我应该如何使用Spring MongoTemplate编写这个？

我尝试了以下,但不起作用:

this.mongoTemplate.updateMulti(new Query(), new Update().pull("tests", "{\"experiment.$id\":\"MyExperiment1\"}"), "user");

谢谢.

Answer 1

看来这很有效:

this.mongoTemplate.updateMulti(new Query(),
        new Update().pull("tests", Query.query(Criteria.where("experiment.$id").is("MyExperiment1"))), USERS_COLLECTION_NAME);