如何在实体框架6中混合使用TPH和TPT?

Ste*_*uer 6 c# inheritance entity-framework ef-code-first entity-framework-6

初步情况

我有一个使用现有数据库的应用程序,目前使用NHibernate作为O/R-Mapper.
现在,我需要使用Code FirstFluent API Configuration迁移到Entity Framework 6.1.1.

但是现在我对部分数据模型有问题,因为它使用不同类型的继承策略(TPT和TPH)

结构体

注意:在这里发布完整的数据模型对我来说似乎有点太大了,所以我在一个小的POC程序中重现了我面临的问题.

CLASS                  | TABLE              | TYPE
-----------------------+--------------------+------
BaseEntity (abstract)  | BaseTable          |
Inherited_TPH          | BaseTable          |  1
Inherited_TPT          | Inherited_TPT      |  2
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调用表中用作描述符的列 Type

根据这个答案,我添加了一个抽象类Intermediate_TPH作为中间层:

类和映射图

一些示例数据:带有ID=3类型的条目Inherited_TPT

数据

这些是我的实体类和我的上下文类:

class MyContext : DbContext
{
    public MyContext ( string connectionString )
        : base ( connectionString )
    {
    }

    public DbSet<Inherited_TPH> TPH_Set { get; set; }
    public DbSet<Inherited_TPT> TPT_Set { get; set; }
    public DbSet<SomethingElse> Another_Set { get; set; }

    protected override void OnModelCreating ( DbModelBuilder modelBuilder )
    {
        modelBuilder
        .Entity<BaseEntity> ()
        .ToTable ( "BaseTable" );

        modelBuilder
        .Entity<Inherited_TPH> ()
        .Map ( t => t.Requires ( "Type" ).HasValue ( 1 ) );

        modelBuilder
        .Entity<Intermediate_TPT> ()
        .Map ( t => t.Requires ( "Type" ).HasValue ( 2 ) );

        modelBuilder
        .Entity<Intermediate_TPT> ()
        .Map<Inherited_TPT> ( t => t.ToTable ( "Inherited_TPT" ) ); 

        modelBuilder
        .Entity<SomethingElse> ()
        .ToTable ( "SomethingElse" )
        .HasKey ( t => t.Id );
    }
}

public abstract class BaseEntity
{
    public virtual int Id { get; set; }
    public virtual string Title { get; set; }
}
public class Inherited_TPH : BaseEntity
{
}
public abstract class Intermediate_TPT : BaseEntity
{
}
public class Inherited_TPT : Intermediate_TPT
{
    public virtual string Comment { get; set; }
}
public class SomethingElse
{
    public virtual string Description { get; set; }
    public virtual int Id { get; set; }
}
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运行以下代码将给我一个错误.

    static void Main ( string[] args )
    {
        Database.SetInitializer<MyContext> ( null );
        var ctx = new MyContext ( @"Data Source=(local);Initial Catalog=nh_ef;Integrated Security=true" );
        try
        {
            // Accessing Inherited_TPH works just fine
            foreach ( var item in ctx.TPH_Set ) Console.WriteLine ( "{0}: {1}", item.Id, item.Title );
            // Accessing Inherited_TPT works just fine
            foreach ( var item in ctx.TPT_Set ) Console.WriteLine ( "{0}: {1} ({2})", item.Id, item.Title, item.Comment );
            // The rror occurs when accessing ANOTHER entity:
            foreach ( var item in ctx.Another_Set ) Console.WriteLine ( "{0}: {1}", item.Id, item.Description );
        }
        catch ( Exception ex )
        {
            Console.WriteLine ( ex.Message );
            if( ex.InnerException != null ) { Console.WriteLine ( ex.InnerException.Message ); }
        }
    }
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产量

该程序产生以下输出:

1:Simpson
2:Johnson
3:Smith(关于SMITH的更多细节)
4:Miller(关于MILLER的更多细节)
准备命令定义时发生错误.有关详细信息,请参阅内部异常

(26,10):错误3032:从第14,26行开始映射片段的问题:EntityTypes PoC.Inherited_TPH,PoC.Inherited_TPT被映射到表BaseEntity中的相同行.映射条件可用于区分这些类型映射到的行.

如您所见,映射似乎有效,因为我可以从Inherited_TPT和加载所有数据Inherited_TPH.但是当访问另一个实体时,我得到一个例外.

我如何配置映射以摆脱此错误并能够访问现有的数据库结构?

Ste*_*uer 4

我终于自己找到了解决方案。我会将其发布在这里,以防其他人需要相同的行为......

  • 在这种情况下不需要中间层
  • 仅 TPH 需要鉴别器

所以我们需要做的就是改变映射的定义:

protected override void OnModelCreating ( DbModelBuilder modelBuilder )
{
    // Not changed
    modelBuilder
        .Entity<BaseEntity> ()
        .ToTable ( "BaseTable" );


    // --- CHANGED ---
    modelBuilder.Entity<BaseEntity> ()
        // TPH => Discriminator
        .Map<Inherited_TPH> ( m => m.Requires ( "Type" ).HasValue ( 1 ).IsOptional () ) 
        // TPT => Mapping to table
        .Map<Inherited_TPT> ( m => m.ToTable ( "Inherited_TPT" ) ); 

    // Not changed
    modelBuilder
        .Entity<SomethingElse> ()
        .ToTable ( "SomethingElse" )
        .HasKey ( t => t.Id );
}
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