man*_*her 13 java sql spring hibernate spring-boot
我有以下实体:
package com.server.models;
@Entity
@Table(name="users")
@NamedQueries({
@NamedQuery(name=User.QUERY_FIND_USER,query="SELECT c FROM user c WHERE c.username = :username")
})
public class User {
public static final String QUERY_FIND_USER = "LoginFindUser";
// ...
}
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然后使用实体管理器(em)我正在执行以下操作:
package com.server.controllers;
@Service
@Transactional
@RestController
@RequestMapping("/user")
public class LoginController {
@PersistenceContext
private EntityManager em;
// my code
TypedQuery<User> queries = em.createNamedQuery(User.QUERY_FIND_USER,User.class).setParameter("username", username);
List<User> users = queries.getResultList();
}
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但是我收到以下错误:
java.lang.IllegalArgumentException: No query defined for that name [LoginFindUser]
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这是我的spring-boot配置.这应该包括扫描实体.
package com.server.boot;
@Configuration
@ComponentScan({"com.server"})
@EnableAutoConfiguration
public class Starter {
public static void main(String[] args){
SpringApplication.run(Starter.class,args);
System.out.println("started application");
}
@Bean
public LoginController loginController(){
return new LoginController();
}
@Bean
public HibernateJpaSessionFactoryBean sessionFactory(EntityManagerFactory emf) {
HibernateJpaSessionFactoryBean factory = new HibernateJpaSessionFactoryBean();
factory.setEntityManagerFactory(emf);
return factory;
}
}
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man*_*her 13
找到了.感谢评论中的人
加
@EntityScan("com.server.models")
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到你的配置类
我只好在查询原因的错误user
是需要User
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