我使用GraphViz库,在某些情况下,它返回一个以元组为键的字典.
{(4, 7): 0, (2, 6): 1, (10, 4): 1, (5, 11): 1, (4, 5): 1,
(2, 8): 0, (8, 11): 0, (10, 0): 1, (6, 11): 1, (9, 11): 1,
(1, 9): 0, (10, 1): 0, (7, 11): 1, (0, 9): 1, (3, 7): 1,
(10, 3): 1, (10, 2): 1}
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出于某种原因,我想得到元组中的第二个数字:第一个数字== 10 , 值== 1
我试过访问字典,(10, )但我认为python中不允许使用这种语法.
答案应该是: [4 ,0 ,3 , 2]
你将不得不迭代字典,例如:
In [1]: d = {(4, 7): 0, (2, 6): 1, (10, 4): 1, (5, 11): 1, (4, 5): 1,
...: (2, 8): 0, (8, 11): 0, (10, 0): 1, (6, 11): 1, (9, 11): 1,
...: (1, 9): 0, (10, 1): 0, (7, 11): 1, (0, 9): 1, (3, 7): 1,
...: (10, 3): 1, (10, 2): 1}
In [2]: [b for (a, b), v in d.items() if a == 10 and v == 1]
Out[2]: [4, 0, 3, 2]
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