创建具有固定数量元素(长度)的范围

Question

在Python 2.7中,如何在具有固定数量元素的范围上创建列表,而不是在每个元素之间固定步长？

>>> # Creating a range with a fixed step between elements is easy:
>>> range(0, 10, 2)
[0, 2, 4, 6, 8]
>>> # I'm looking for something like this:
>>> foo(0, 10, num_of_elements=4)
[0.0, 2.5, 5, 7.5]

Answer 1

我为此使用了numpy.

>>> import numpy as np
>>> np.linspace(start=0, stop=7.5, num=4)
array([ 0. ,  2.5,  5. ,  7.5])
>>> list(_)
[0.0, 2.5, 5.0, 7.5]

Answer 2

您可以使用列表理解轻松生成这样的列表:

def foo(start, stop, count):
    step = (stop - start) / float(count)
    return [start + i * step for i in xrange(count)]

这会产生:

>>> foo(0, 10, 4)
[0.0, 2.5, 5.0, 7.5]