我有以下代码,
@checkedin=[]
@accepted=[]
@rejected=[]
result.each do |parse_order|
orderId = parse_order['orderID']
if parse_order['status'] == -1
@rejected << orderId
elsif parse_order['status'] == 1
@accepted << [orderId, parse_order['createdAt']]
elsif parse_order['status'] == 2
@checkedin << [orderId, parse_order['createdAt']]
elsif parse_order['status'] == 3
next
end
end
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有没有更好的方法来简洁它.谢谢.
您可以使用单行条件.此外,next在块结束时是不必要的.
@checkedin = []
@accepted = []
@rejected = []
result.each do |parse_order|
orderId = parse_order['orderID']
status = parse_order['status']
@rejected << orderId if status == -1
@accepted << [orderId, parse_order['createdAt']] if status == 1
@checkedin << [orderId, parse_order['createdAt']] if status == 2
end
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