Ionic创建新的sass文件

Question

我正在为我的html5移动应用程序使用Ionic框架.

我知道我可以在scss文件夹下的ionic.app.scss文件中添加自定义sass,离子服务或离子构建会将我的sass编译成css,但是如果我想在这里添加额外的sass文件,例如ionic.home.scss如何编译这些？我是否需要修改gulp文件.

我基本上扩展了默认的Ionic选项卡应用程序.这是我想要的结构,基本上是每个模板的sass文件

+-- _gulpfile.js
+-- _scss
|   +-- ionic.app.scss
|   +-- tab-home.scss
|   +-- tab-projects.scss
|   +-- tab-services.scss
+-- _templates
|   +-- tab-home.html
|   +-- tab-projects.html
|   +-- tab-services.html
+-- index.html

这是gulp文件

var gulp = require('gulp');
var gutil = require('gulp-util');
var bower = require('bower');
var concat = require('gulp-concat');
var sass = require('gulp-sass');
var minifyCss = require('gulp-minify-css');
var rename = require('gulp-rename');
var sh = require('shelljs');

var paths = {
  sass: ['./scss/**/*.scss']
};

gulp.task('default', ['sass']);

gulp.task('sass', function(done) {
  gulp.src('./scss/ionic.app.scss')
    .pipe(sass())
    .pipe(gulp.dest('./www/css/'))
    .pipe(minifyCss({
      keepSpecialComments: 0
    }))
    .pipe(rename({ extname: '.min.css' }))
    .pipe(gulp.dest('./www/css/'))
    .on('end', done);
});

gulp.task('watch', function() {
  gulp.watch(paths.sass, ['sass']);
});

gulp.task('install', ['git-check'], function() {
  return bower.commands.install()
    .on('log', function(data) {
      gutil.log('bower', gutil.colors.cyan(data.id), data.message);
    });
});

gulp.task('git-check', function(done) {
  if (!sh.which('git')) {
    console.log(
      '  ' + gutil.colors.red('Git is not installed.'),
      '\n  Git, the version control system, is required to download Ionic.',
      '\n  Download git here:', gutil.colors.cyan('http://git-scm.com/downloads') + '.',
      '\n  Once git is installed, run \'' + gutil.colors.cyan('gulp install') + '\' again.'
    );
    process.exit(1);
  }
  done();
});

Answer 1

您可以只使用一个ionic.app.scss并@import在此文件中扩展它.

@import "tab-home.scss", "tab-projects.scss", "tab-services.scss";