首先,通过调用100来取数百位数并通过调用方法打印相应的数字, numberToWord((number / 100), " HUNDRED");因为数字/ 100将在0到9之间,因此它将在由HUNDRED连接的单词中打印数字.
现在你留下了两个数字,你直接打电话,numberToWord((number % 100), " ");因为我们采用模数100的模数,所以它只传递两位数.if (num > 19) {System.out.print(tens[num / 10] + " " + ones[num % 10]);}然后它将需要几十个位置并打印十个单词连接的单词.else {System.out.print(ones[num]);}直接从数组中打印1到19之间的单词.
import java.util.Scanner;
public class Test1 {
public static void main(String[] args) {
int number = 0;
Scanner scanner = new Scanner(System.in);
System.out.print("Please type a number between 0 and 999 OR type -1 to exit: ");
number = scanner.nextInt();
while(number!=-1){
if(number>=0 && number<=999){
if(number==0){
System.out.print("NUMBER AFTER CONVERSION:\tZERO");
} else {
System.out.print("NUMBER AFTER CONVERSION:\t");
numberToWord(((number / 100) % 10), " HUNDRED");
numberToWord((number % 100), " ");
}
} else{
System.out.print("NUMBER OUT OF RANGE");
}
System.out.print("\nPlease type a number between 0 and 999 OR type -1 to exit: ");
number = scanner.nextInt();
}
}
public static void numberToWord(int num, String val) {
String ones[] = {" ", " ONE", " TWO", " THREE", " FOUR", " FIVE", " SIX", " SEVEN", " EIGHT", " NINE", " TEN", " ELEVEN", " TWELVE", " THIRTEEN", " FOURTEEN", " FIFTEEN", " SIXTEEN", " SEVENTEEN", " EIGHTEEN", " NINETEEN"
};
String tens[] = {" ", " ", " TWENTY", " THIRTY", " FOURTY", " FIFTY", " SIXTY", " SEVENTY", " EIGHTY", " NINETY"};
if (num > 19) {
System.out.print(tens[num / 10] + " " + ones[num % 10]);
} else {
System.out.print(ones[num]);
}
if (num > 0) {
System.out.print(val);
}
}
}
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样本输出:
Please type a number between 0 and 999 OR type -1 to exit: 563
NUMBER AFTER CONVERSION: FIVE HUNDRED SIXTY THREE
Please type a number between 0 and 999 OR type -1 to exit: 45
NUMBER AFTER CONVERSION: FOURTY FIVE
Please type a number between 0 and 999 OR type -1 to exit: 6
NUMBER AFTER CONVERSION: SIX
Please type a number between 0 and 999 OR type -1 to exit: 0
NUMBER AFTER CONVERSION: ZERO
Please type a number between 0 and 999 OR type -1 to exit: -1
exit
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这是 Number to Word 程序的递归解决方案
string unitsMap[] = { "zero", "one", "two", "three", "four", "five","six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen" };
string tensMap[] = { "zero", "ten", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety" };
string NumberToWords(int number)
{
if (number == 0)
return "zero";
if (number < 0)
return "minus " + NumberToWords(abs(number));
string words = "";
if ((number / 1000000000) > 0)
{
words += NumberToWords(number / 1000000000) + " billion ";
number %= 1000000000;
}
if ((number / 1000000) > 0)
{
words += NumberToWords(number / 1000000) + " million ";
number %= 1000000;
}
if ((number / 1000) > 0)
{
words += NumberToWords(number / 1000) + " thousand ";
number %= 1000;
}
if ((number / 100) > 0)
{
words += NumberToWords(number / 100) + " hundred ";
number %= 100;
}
if (number > 0)
{
if (number < 20)
words += unitsMap[number];
else
{
words += tensMap[number / 10];
if ((number % 10) > 0)
words += "-" + unitsMap[number % 10];
}
}
return words;
}
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