将Java对象转换为XML字符串

Question

是的,是的,我知道有很多关于这个主题的问题.但我仍然无法找到解决问题的方法.我有一个属性注释的Java对象.例如Customer,就像在这个例子中一样.我想要一个String表示它.谷歌建议将JAXB用于此类目的.但是在所有示例中,创建的XML文件都打印到文件或控制台,如下所示:

File file = new File("C:\\file.xml");
JAXBContext jaxbContext = JAXBContext.newInstance(Customer.class);
Marshaller jaxbMarshaller = jaxbContext.createMarshaller();

// output pretty printed
jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

jaxbMarshaller.marshal(customer, file);
jaxbMarshaller.marshal(customer, System.out);

但我必须使用此对象并以XML格式通过网络发送.所以我想得到一个代表XML的String.

String xmlString = ...
sendOverNetwork(xmlString);

我怎样才能做到这一点？

Answer 1

您可以使用Marshaler的编组方法将Writer作为参数:

元帅(对象,作家)

并传递一个可以构建String对象的Implementation

直接已知子类: BufferedWriter,CharArrayWriter,FilterWriter,OutputStreamWriter,PipedWriter,PrintWriter,StringWriter

调用其toString方法以获取实际的String值.

这样做:

StringWriter sw = new StringWriter();
jaxbMarshaller.marshal(customer, sw);
String xmlString = sw.toString();

Answer 2

一个方便的选择是使用javax.xml.bind.JAXB:

StringWriter sw = new StringWriter();
JAXB.marshal(customer, sw);
String xmlString = sw.toString();

反向过程(unmarshal)将是:

Customer customer = JAXB.unmarshal(new StringReader(xmlString), Customer.class);

这种方法无需处理已检查的异常.

Answer 3

正如A4L所提到的,你可以使用StringWriter.这里提供示例代码:

private static String jaxbObjectToXML(Customer customer) {
    String xmlString = "";
    try {
        JAXBContext context = JAXBContext.newInstance(Customer.class);
        Marshaller m = context.createMarshaller();

        m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE); // To format XML

        StringWriter sw = new StringWriter();
        m.marshal(customer, sw);
        xmlString = sw.toString();

    } catch (JAXBException e) {
        e.printStackTrace();
    }

    return xmlString;
}

Answer 4

你可以将它编组为a StringWriter并抓住它的字符串.来自toString().

Answer 5

在 Java 中将对象转换为 XML

客户.java

package com;

import java.util.ArrayList;
import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;

/**
*
* @author ABsiddik
*/

@XmlRootElement
public class Customer {

int id;
String name;
int age;

String address;
ArrayList<String> mobileNo;


 public int getId() {
    return id;
}

@XmlAttribute
public void setId(int id) {
    this.id = id;
}

public String getName() {
    return name;
}

@XmlElement
public void setName(String name) {
    this.name = name;
}

public int getAge() {
    return age;
}

@XmlElement
public void setAge(int age) {
    this.age = age;
}

public String getAddress() {
    return address;
}

@XmlElement
public void setAddress(String address) {
    this.address = address;
}

public ArrayList<String> getMobileNo() {
    return mobileNo;
}

@XmlElement
public void setMobileNo(ArrayList<String> mobileNo) {
    this.mobileNo = mobileNo;
}


}

ConvertObjToXML.java

package com;

import java.io.File;
import java.io.StringWriter;
import java.util.ArrayList;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.Marshaller;

/**
*
* @author ABsiddik
*/
public class ConvertObjToXML {

public static void main(String args[]) throws Exception
{
    ArrayList<String> numberList = new ArrayList<>();
    numberList.add("01942652579");
    numberList.add("01762752801");
    numberList.add("8800545");

    Customer c = new Customer();

    c.setId(23);
    c.setName("Abu Bakar Siddik");
    c.setAge(45);
    c.setAddress("Dhaka, Bangladesh");
    c.setMobileNo(numberList);

    File file = new File("C:\\Users\\NETIZEN-ONE\\Desktop \\customer.xml");
    JAXBContext jaxbContext = JAXBContext.newInstance(Customer.class);
    Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
    jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

    jaxbMarshaller.marshal(c, file);// this line create customer.xml file in specified path.

    StringWriter sw = new StringWriter();
    jaxbMarshaller.marshal(c, sw);
    String xmlString = sw.toString();

    System.out.println(xmlString);
}

}

尝试这个例子..