'str'不支持Python2的缓冲区接口Python3

Question

你好Py2中的这两个功能工作正常,但它不适用于Py3

def encoding(text, codes):
    binary = ''
    f = open('bytes.bin', 'wb')
    for c in text:
        binary += codes[c]
    f.write('%s' % binary)
    print('Text in binary:', binary)
    f.close()
    return len(binary)

def decoding(codes, large):
    f = file('bytes.bin', 'rb')
    bits = f.read(large)
    tmp = ''
    decode_text = ''
    for bit in bits:
        tmp += bit
        if tmp in fordecodes:
            decode_text += fordecodes[tmp]
            tmp = ''
    f.close()
    return decode_text

控制台输出:

Traceback (most recent call last):
  File "Practica2.py", line 83, in <module>
    large = encoding(text, codes)
  File "Practica2.py", line 56, in encoding
    f.write('%s' % binary)
TypeError: 'str' does not support the buffer interface

Answer 1

修复对我来说很简单

使用

f = open('bytes.bin', 'w')

代替

f = open('bytes.bin', 'wb') 

在python 3 'w'中你需要的不是'wb'.

Answer 2

在Python 2中,裸文字字符串(例如'string')是字节,而在Python 3中它们是unicode.这意味着如果您希望在Python 3中将文字字符串视为字节,则必须明确标记它们.

因此,例如,encoding函数的前几行应如下所示:

binary = b''
f = open('bytes.bin', 'wb')
for c in text:
    binary += codes[c]
f.write(b'%s' % binary)

并且在另一个功能中有几行需要类似的处理.

有关更多详细信息,请参阅移植到Python 3,以及字节,字符串和Unicode部分.