使用该行的id编辑表的特定行

Question

我使用php以表格的形式从数据库中显示了一些值.该表的一列保留用于编辑.我希望可以编辑表格的每一行.

编辑代码是

echo"<td class='success'><button class='btn blue' data-toggle='modal' data-target='#myeditModal'>Edit </button></td>";

模态中使用的代码是

<div class="modal fade" id="myeditModal" tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true">
    <div class="modal-dialog">
        <div class="modal-content">
            <div class="modal-header">
                <button type="button" class="close" data-dismiss="modal"><span aria-hidden="true">&times;</span><span class="sr-only">Close</span></button>
                <h4 class="modal-title" id="myModalLabel">Edut Treatment</h4>
            </div>

            <div class="modal-body">
                <form class="form-horizontal" role="form" action="edit.php?id="$row['id']"" enctype="multipart/form-data" method="post">
                    <div class="form-group">
                        <label class="col-lg-4 control-label"> Name</label>
                            <div class="col-lg-6">
                                <input class="form-control" value="" type="text" name="name" >
                            </div>
                    </div>

                    <div class="form-group">
                    <label class="col-md-3 control-label"></label>
                        <div class="col-md-8">
                            <input class="btn btn-primary" value="Save Changes" type="submit" name="submit">

                            <span></span>
                        </div>  
                    </div>
                </form>

            </div>
            <div class="modal-footer">
                <button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
            </div>
        </div>
    </div>
</div>

edit.php页面的代码是

<?php
include('admin_session.php');
$con=mysqli_connect("localhost","root","","db");

// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

$id = $_GET['id'];

mysqli_query($con,"UPDATE treatment_type SET name='".$name.'" WHERE id='".$id."'");
mysqli_close($con);
header("Location: abc.php");
?> 

我的问题是,当我到达edit.php页面时,我得到的URL如下:http://example.com/xyz/edit.php?id=

我无法携带id,因为我无法编辑表格的特定行.