Android - loopJ AsyncHttpClient返回响应onFinish或onSuccess

Question

我正在寻找一种方法来返回我在loopJ AsyncHttpClient onFinish或onSuccess或onFailure中得到的响应.截至目前,我有这段代码:

**jsonParse.java file**
public class jsonParse {
    static JSONObject jObj = null;
    static String jsonString = "";
    AsyncHttpClient client;

      public JSONObject getJSONObj() {
            RequestParams params;
            params = new RequestParams();
            params.add("username", "user");
            params.add("password", "password");
            client = new AsyncHttpClient();
            client.post("http://example.com", params, new TextHttpResponseHandler() {

                @Override
                public void onSuccess(int i, Header[] headers, String response) {
                    jsonString = response;
                    Log.d("onSuccess: ", jsonString);
                }

                @Override
                public void onFailure(int statusCode, Header[] headers, String response, Throwable e) {
                    if (statusCode == 401) {
                        jsonString = response;
                        Log.d("onFailure: ", jsonString);
                    }
                }

            });
            try {
                jObj = new JSONObject(jsonString);
            } catch (JSONException e) {
                Log.e("Exception", "JSONException " + e.toString());
            }
            return jObj;
        }
}

当我调用代码时:

JSONParser jsonParser = new JSONParser();
jsonParser.getJSONFromUrl(); 

我在onSuccess或onFailure方法完成http帖子之前得到了JSONException.

我注意到,在第一次调用时:Log.e("Exception","JSONException"+ e.toString()); 正在记录,然后Log.d("onSuccess:",jsonString); 记录值,因为它们处于同步状态.

在第二次调用:jObj = new JSONObject(jsonString); 成功执行并获得该方法的所需返回值,因为到那时onSuccess方法已经将值赋给变量jsonString.

现在我正在寻找的是一种防止jObj从方法中过早返回的方法.

反正有没有制作方法,getJSONObj,等待AsyncHttpClient任务的完成,将变量分配到jsonString,创建JSONObject并返回它？

提前致谢!干杯!

Answer 1

使用界面.这样您就可以创建自己的回调,其方法可以从onSuccess或onFailure调用.

public interface OnJSONResponseCallback {
    public void onJSONResponse(boolean success, JSONObject response);
}

public JSONObject getJSONObj(OnJSONResponseCallback callback) {
    ...
   @Override
   public void onSuccess(int i, Header[] headers, String response) {
       try {
           jObj = new JSONObject(response);
           callback.onJSONResponse(true, jObj);
       } catch (JSONException e) {
           Log.e("Exception", "JSONException " + e.toString());
       }
   }

   @Override
   public void onFailure(int statusCode, Header[] headers, String response, Throwable e) {
       try {
           jObj = new JSONObject(response);
           callback.onJSONResponse(false, jObj);
       } catch (JSONException e) {
           Log.e("Exception", "JSONException " + e.toString());
       }
   }
}

并称之为:

jsonParse.getJSONObj(new OnJSONResponseCallback(){
    @Override
    public void onJSONResponse(boolean success, JSONObject response){
       //do something with the JSON
    }
});