eng*_*ran 5 rest http http-status-codes strongloop loopbackjs
我正在尝试修改create的http状态代码.
POST /api/users
{
"lastname": "wqe",
"firstname": "qwe",
}
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返回200而不是201
我可以为错误做些类似的事情:
var err = new Error();
err.statusCode = 406;
return callback(err, info);
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但是我找不到如何更改create的状态代码.
我找到了创建方法:
MySQL.prototype.create = function (model, data, callback) {
var fields = this.toFields(model, data);
var sql = 'INSERT INTO ' + this.tableEscaped(model);
if (fields) {
sql += ' SET ' + fields;
} else {
sql += ' VALUES ()';
}
this.query(sql, function (err, info) {
callback(err, info && info.insertId);
});
};
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在您的通话中,remoteMethod
您可以直接向响应添加功能.这是通过以下rest.after
选项完成的:
function responseStatus(status) {
return function(context, callback) {
var result = context.result;
if(testResult(result)) { // testResult is some method for checking that you have the correct return data
context.res.statusCode = status;
}
return callback();
}
}
MyModel.remoteMethod('create', {
description: 'Create a new object and persist it into the data source',
accepts: {arg: 'data', type: 'object', description: 'Model instance data', http: {source: 'body'}},
returns: {arg: 'data', type: mname, root: true},
http: {verb: 'post', path: '/'},
rest: {after: responseStatus(201) }
});
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注意:如果context.result
值为false ,似乎strongloop将强制204"无内容" .为了解决这个问题,我只需{}
使用我想要的状态代码传回一个空对象.
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