使用UploadedFile上传文件类型问题

Ash*_*thi 2 php file-upload symfony mime-types is-uploaded-file

UploadedFile在symfony2中使用类来上传图像文件.我已经允许MIME类型的图像image/jpgimage/png.当我将png文件从我的系统上传到服务器时,其mime类型会自动更改.我知道它改变了,因为当我发出这个命令:

file --mime-type /home/mysuer/img.png
Run Code Online (Sandbox Code Playgroud)

它给了我这个:

home/myuser/img.png: image/png
Run Code Online (Sandbox Code Playgroud)

但是当我上传文件和打印UploadedFile对象时,它会提供以下输出:

Array
(
    [media] => Symfony\Component\HttpFoundation\File\UploadedFile Object
        (
            [test:Symfony\Component\HttpFoundation\File\UploadedFile:private] => 
            [originalName:Symfony\Component\HttpFoundation\File\UploadedFile:private] => img.png
            [mimeType:Symfony\Component\HttpFoundation\File\UploadedFile:private] => application/octet-stream
            [size:Symfony\Component\HttpFoundation\File\UploadedFile:private] => 1246
            [error:Symfony\Component\HttpFoundation\File\UploadedFile:private] => 0
            [pathName:SplFileInfo:private] => /tmp/phpivgnne
            [fileName:SplFileInfo:private] => phpivgnne
        )

)
Run Code Online (Sandbox Code Playgroud)

任何人都可以说明什么是错的?

编辑

这是我的代码:

public function postFileAction(Request $request)
{
    print_r($request->files->all());//Prints All files


    $image = $request->files->get('media');
    echo $image->getClientMimeType();exit; //Mime Type Information

    if (empty($image)) {
        throw new FileException('Invalid File, Please Select a Valid File.');
    }

    $uploader = $this->get('application.file_uploader');

    if (!$this->container->get('security.context')->isGranted('IS_AUTHENTICATED_FULLY')) {
        //authenticated (NON anonymous users)
        throw new InvalidParameterException('Invalid User, Please use valid credentials');
    }

    return $uploader->upload($image, $this->get('security.context')->getToken()->getUser()->getId());
}
Run Code Online (Sandbox Code Playgroud)

PHPUnit测试代码

public function testPostFile()
{
    $file    = tempnam(sys_get_temp_dir(), 'upl'); // create file
    imagepng(imagecreatetruecolor(10, 10), $file); // create and write image/png to it
    $image   = new UploadedFile($file, 'new_image.png', 'image/png', 10, UPLOAD_ERR_OK);
    $crawler = $this->client->request(
            'POST', '/api/v1/files.json', array('submit' => 'Submit Form'), array('media' => $image)
    );

    $response = $this->client->getResponse();

    $this->assertJsonResponse($response);
    $this->assertContains('filename', $response->getContent());

    print_r($response->getContent());exit;

    $fileToken = json_decode($response->getContent());
    $this->assertNotEmpty($fileToken->filename);

    unlink($file);
    unset($file, $image, $crawler, $response);

    return $fileToken->filename;
}
Run Code Online (Sandbox Code Playgroud)

我正在使用curl命令提示符来测试我的REST Web服务文件上传,如下所示:

curl -X POST myapi.com/app_dev.php/api/v1/files.json --form "media=@/home/myuser/img.png"
Run Code Online (Sandbox Code Playgroud)

Ash*_*thi 6

最后我得到了我的问题的解决方案将发布core-php和symfony2的问题的答案.

核心PHP(可在http://php.net/manual/en/features.file-upload.php上找到):

// DO NOT TRUST $_FILES['upfile']['mime'] VALUE !!
// Check MIME Type by yourself.
$finfo = new finfo(FILEINFO_MIME_TYPE);
if (false === $ext = array_search(
    $finfo->file($_FILES['upfile']['tmp_name']),
    array(
        'jpg' => 'image/jpeg',
        'png' => 'image/png',
        'gif' => 'image/gif',
    ),
    true
)) {
    throw new RuntimeException('Invalid file format.');
}
Run Code Online (Sandbox Code Playgroud)

所以永远不要相信$_FILES['upfile']['mime']总是使用fileinfo,这给了我线索.

对于Symfony2:

所以我开始查看我的代码并发现我正在使用$file->getClientMimeType(),这不是很好,我们必须使用$file->getMimeType()哪些用于fileinfo获取mime类型并将提供正确的mime类型.

getMimeType()MIME类型是使用猜到MimeTypeGuesser实例,它使用finfo(),mime_content_type()并且该系统二进制"文件"(按此次序),这取决于哪个那些是可用的.

谢谢大家的帮助:D