当使用object参数传递此信息时,为什么Enum.GetName()要求输入？

Question

考虑.NET函数签名:

Enum.GetName(Type type, object o);

似乎完全不需要询问Type何时传递此信息object o

以下代码说明了这一点:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace ConsoleApplication1
{
    public enum Color
    {
        Black, White, Red, Orange, Yellow, Green, Blue, Purple, Pink,
        DarkRed, DarkGreen, DarkBlue,
        NeonGreen, NeonBlue
    }
    class Program
    {
        private static Random rand = new Random();

        static void Main(string[] args)
        {
            Color color = getRandomColor();
            PrintType(color);
            Console.WriteLine("typeof = " + typeof(Color));
            Console.ReadLine();
        }

        public static void PrintType(object o) 
        {
            Type type = o.GetType();
            Console.WriteLine("type = " + type);
        }

        private static Color getRandomColor()
        {
            var values = Enum.GetValues(typeof(Color));
            Color randomColor = (Color)values.GetValue(rand.Next(values.Length));
            return randomColor;
        }
    }
}

输出是

type = ConsoleApplication1.Color
typeof = ConsoleApplication1.Color

这意味着Enum.GetName()方法签名可能如下所示:

Enum.GetName(object o);

Answer 1

o不需要是类型Color.例:

Enum.GetName(typeof(Color), 3) // == Orange