private int currentSpeed;
private static final int MAXIMUM_SPEED = 100;
private int heading;
int speedUp(int increaseBy) {
currentSpeed += increaseBy;
return currentSpeed;
}
int slowDown(int decreaseBy) {
currentSpeed -= decreaseBy;
return currentSpeed;
}
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如何防止值currentSpeed超出MAXIMUM_VALUEspeedUp方法中的变量,并且在slowDown不使用if语句的情况下从方法中降低0以下.我相信使用Math.min&Math.max 会工作,但我不确定如何实施.
使用Math.max和Math.min如下:
int speedUp(int increaseBy) {
currentSpeed = Math.min(currentSpeed + increaseBy,MAXIMUM_SPEED);
return currentSpeed;
}
int slowDown(int decreaseBy) {
currentSpeed = Math.max(currentSpeed - decreaseBy,0);
return currentSpeed;
}
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