在c#中覆盖Json属性名称

Question

我有一个包含以下字段的课程.当需要调用外部rest API方法时,这些属性用于序列化为json对象.

public class Customer
    {
        [JsonProperty(PropertyName = "email")]
        public string Email { get; set; }

        [JsonProperty(PropertyName = "prop[listId]")]
        public string Test{ get; set; }

        // there are lot of properties 
    }

在属性名称中Test,外部API服务调用需要一些像json文件名格式之类的东西.

prop[7]

在我的情况下,这7可以根据test,dev和prod等环境进行更改.所以我正在寻找将listId值移动到app.config中的方法.

我试图按照以下方式执行此操作,但不允许这样做.因为listIdValue如果指定常量值,它将起作用.

     private string listIdValue = ConfigurationManager.AppSettings["ListIdValue"];

     [JsonProperty(PropertyName = "prop["+listIdValue +"]")]
     public string Test{ get; set; }

Answer 1

您必须覆盖DefaultContractResolver并实现自己的机制来提供PropertyName(在JSON中).我将提供一个完整的示例代码,以显示运行时生成的反序列化和序列化PropertyName.目前,它将Test字段修改为Test5(在所有模型中).您应该实现自己的机制(使用属性,保留名称,表或其他.

class Program
{
    static void Main(string[] args)
    {
        var customer = new Customer() {Email = "asd@asd.com", Test = "asdasd"};
        var a = Serialize(customer, false);
        var b = Serialize(customer, true);
        Console.WriteLine(a);
        Console.WriteLine(b);

        var desA = Deserialize<Customer>(a, false);
        var desB = Deserialize<Customer>(b, true);

        Console.WriteLine("TestA: {0}", desA.Test);
        Console.WriteLine("TestB: {0}", desB.Test);

    }

    static string Serialize(object obj, bool newNames)
    {
        JsonSerializerSettings settings = new JsonSerializerSettings();
        settings.Formatting = Formatting.Indented;
        if (newNames)
        {
            settings.ContractResolver = new CustomNamesContractResolver();
        }

        return JsonConvert.SerializeObject(obj, settings);
    }
    static T Deserialize<T>(string text, bool newNames)
    {
        JsonSerializerSettings settings = new JsonSerializerSettings();
        settings.Formatting = Formatting.Indented;
        if (newNames)
        {
            settings.ContractResolver = new CustomNamesContractResolver();
        }

        return JsonConvert.DeserializeObject<T>(text, settings);
    }
}
class CustomNamesContractResolver : DefaultContractResolver
{
    protected override IList<JsonProperty> CreateProperties(System.Type type, MemberSerialization memberSerialization)
    {
        // Let the base class create all the JsonProperties 
        // using the short names
        IList<JsonProperty> list = base.CreateProperties(type, memberSerialization);

        // Now inspect each property and replace the 
        // short name with the real property name
        foreach (JsonProperty prop in list)
        {
            if (prop.UnderlyingName == "Test") //change this to your implementation!
                prop.PropertyName = "Test" + 5;

        }

        return list;
    }
}

public class Customer
{
    [JsonProperty(PropertyName = "email")]
    public string Email { get; set; }

    public string Test { get; set; }

}

输出:

{
  "email": "asd@asd.com",
  "Test": "asdasd"
}
{
  "email": "asd@asd.com",
  "Test5": "asdasd"
}
TestA: asdasd
TestB: asdasd

如您所见,当我们使用时Serialize(..., false)- 字段的名称是Test,当我们使用时Serialize(..., true)- 字段的名称是Test5,如预期的那样.这也适用于反序列化.

我用这个答案作为我的答案的检查:https://stackoverflow.com/a/20639697/773879