蝙蝠将新行字符替换为"|"

Question

我想将新行字符替换为"|" 使用Window bat.

例如file1:

1
2
3

输出:

1|2|3

我试试这个蝙蝠:

echo off
setlocal enabledelayedexpansion
for /f "delims=" %%a in (123.txt) do (
set a=%%a
set a=!a:"\r\n"=^|!
for  %%b in ("!a!") do (
echo.%%~b>>1245.txt
))
pause

但是,新行char不是"\ r \n".如何获取新的行char表达式？

Answer 1

@echo off
setlocal EnableDelayedExpansion

rem Initialize the output line
set "line="

rem Catenate all file lines in the same variable separated by "|"
for /F "delims=" %%a in (123.txt) do set "line=!line!|%%a"

rem Show final line, removing the leading "|"
echo !line:~1!>>1245.txt