SQL 连接两个 ID 匹配的表

Question

我的数据库中有两个表。

Movies 桌子：

+----------------------------------------
| ID | title                | timestamp |
+----------------------------------------
| 1  | The host             | time      |
| 2  | Fight Club           | time      |
| 4  | 21                   | time      |
----------------------------------------+

Movie_Links 桌子：

+---------------------------------------+
| ID | link                 | movie_id  |
+---------------------------------------+
| 1  | some link            | 1         |
| 2  | some link            | 1         |
| 3  | some link            | 1         |
+---------------------------------------+

目前我只从Movies表中选择行title，例如：

SELECT * FROM `Movies` 
WHERE `title` LIKE '%The Host%' 
ORDER BY `timestamp` DESC DESC LIMIT 30

但我想要做的是与上面相同的查询，但连接Movie_Links表，其中movie_id等于Movies表的ID并获取所有具有Movie_id等于1.

Answer 1

SQL 连接两个 ID 匹配的表

SELECT *
FROM Movies 
LEFT JOIN Movie_Links 
ON Movies.ID = Movie_Links.movie_id;

Answer 2

测试以下查询：

SELECT ml.id,m.title,m.timestamp, ml.link
FROM movies m ,Movie_Links ml
WHERE m.id=ml.movie_id and title LIKE '%The Host%'

BR,

Answer 3

只需加入匹配的列即可：

SELECT * FROM movies m
JOIN MovieLinks ml
ON ml.movie_id = m.id
WHERE m.title LIKE '%The Host%'