Chr*_*ans 0 java constructor class object
我正在制定一个程序,将银行账户作为对象.这些帐户具有利率,余额,ID和日期创建数据.根据我的理解,默认余额,ID和兴趣是0.默认情况下,利率未定义.我正在学习的那本书表明,使用"Circle(){}"完成了一个无参数的构造函数.我在帐户类中使用了"account(){}".当我在jGRASP中运行程序时,我得到两个构造函数的错误"无效的方法声明;返回类型".它正在认识到我打算将构造函数作为方法.我需要了解什么才能让我的构造函数不被认为是方法?
在运行第一个构造函数时,我理解我们使用默认值创建一个名为account的Account对象.当我们运行第二个构造函数时,我们将帐户对象的值更改为指定的值
public class Bank{
public static void main(String[] args){
Account account = new Account(1122, 20000);
account.setAnnualInterestRate(4.5);
account.withdraw(2500);
account.deposit(3000);
System.out.println("Balance is " + account.getBalance());
System.out.println("Monthly interest is " + account.getMonthlyInterest());
System.out.println("This account was created at " + account.getDateCreated());
}
}
class Account {
private int id = 0;
private double balance = 0;
private double annualInterestRate = 0;
private String dateCreated;
account(){
}
account(int newID, double newBalance){
id = newID;
balance = newBalance;
}
//accessor for ID
public int getID(){
return id;
}
//acessor for balance
public double getBalance(){
return balance;
}
//accessor for interest rate
public double getAnnualInterest(){
return annualInterestRate;
}
//mutator for ID
public void setID(int IDset){
id = IDset;
}
//mutator for balance
public void setBalance(int BalanceSet){
balance = BalanceSet;
}
//mutator for annual interest
public void setAnnualInterestRate(double InterestSet){
annualInterestRate = InterestSet;
}
//accessor for date created
public String getDateCreated(){
return dateCreated;
}
//method that converts annual interest into monthly interest and returns the value
public double getMonthlyInterest(){
double x = annualInterestRate / 12;
return x;
}
//method that witdraws from account
public double withdraw(double w){
balance -= w;
return balance;
}
//method that deposits into account
public double deposite(double d){
balance += d;
return balance;
}
}
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rge*_*man 10
构造函数名称必须以区分大小写的方式匹配类名称.在Account课堂上,改变
account(){
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至
Account(){
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同样适用于你的其他构造函数.
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