如何序列化List <object>

Question

我正在编写常用函数来序列化给定对象和List <object>,如下所示

public string SerializeObject(Object pObject)// for given object
{
    try
    {
        String XmlizedString = null;
        MemoryStream memoryStream = new MemoryStream();
        XmlSerializer xs = new XmlSerializer(typeof(pObject));
        XmlTextWriter xmlTextWriter = new XmlTextWriter(memoryStream, Encoding.UTF8);
        xs.Serialize(xmlTextWriter, pObject);
        memoryStream = (MemoryStream)xmlTextWriter.BaseStream;
        XmlizedString = UTF8ByteArrayToString(memoryStream.ToArray());
        return XmlizedString;
    }
    catch (Exception e) { System.Console.WriteLine(e); return null; }
}

public string SerializeObject(List<Object> pObject)// for given List<object>
{
    try
    {
        String XmlizedString = null;
        MemoryStream memoryStream = new MemoryStream();
        XmlSerializer xs = new XmlSerializer(typeof(pObject));
        XmlTextWriter xmlTextWriter = new XmlTextWriter(memoryStream, Encoding.UTF8);
        xs.Serialize(xmlTextWriter, pObject);
        memoryStream = (MemoryStream)xmlTextWriter.BaseStream;
        XmlizedString = UTF8ByteArrayToString(memoryStream.ToArray());
        return XmlizedString;
    }
    catch (Exception e) { System.Console.WriteLine(e); return null; }
}

第一个工作正常.如果我传递任何类型,它会成功返回xml字符串.

更正:第二次出现编译错误(错误:无法转换List<MyType>为List<object>.

我重写第二个如下解决了我的问题.现在它正在序列化给定的List<generic types>.

private string SerializeObject<T>(T source)
{
    MemoryStream memoryStream = new MemoryStream();
    XmlSerializer xs = new XmlSerializer(typeof(T));
    XmlTextWriter xmlTextWriter = new XmlTextWriter(memoryStream, Encoding.UTF8);
    xs.Serialize(xmlTextWriter, source);
    memoryStream = (MemoryStream)xmlTextWriter.BaseStream;
    string XmlizedString = UTF8ByteArrayToString(memoryStream.ToArray());
    return XmlizedString;
}

Answer 1

https://weblogs.asp.net/rajbk/Contents/Item/Display/345

文章中的相关代码：

private static string SerializeObject<T>(T source)
{
    var serializer = new XmlSerializer(typeof(T));
    using (var sw = new System.IO.StringWriter())
    using (var writer = XmlWriter.Create(sw))
    {
        serializer.Serialize(writer, source);
        return sw.ToString();
    }
}