从程序集调用printf时,字符串输出两次

Leg*_*ion 0 c x86 assembly nasm

当调用printf向控制台显示状态消息时,它会输出两次.不知道为什么.我希望我的输出是:

Generating move list file...
Done
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但相反,我得到:

Generating move list file...
Done
Done
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由于某种原因,我得到了重复的"完成".

[SECTION .data]
GenMsg:     db "Generating move list file...",10
DoneMsg:    db "Done",10

extern printf

[SECTION .bss]

[SECTION .text]
global main

main:
push ebp            ; set up stack frame
mov ebp,esp
push ebx            ; save regs
push esi
push edi

push GenMsg         ; push addr of gen msg on stack
call printf         ; display gen msg
add esp,4           ; clean up stack 1 parm * 4 = 4 bytes

push DoneMsg        ; push addr of done msg on stack
call printf         ; display done msg
add esp,4           ; clean up stack 1 parm * 4 = 4 bytes

exit:
pop edi             ; restore regs
pop esi
pop ebx
mov esp,ebp         ; destroy stack frame
pop ebp
ret
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Mic*_*ael 6

您的字符串未正确地以空值终止.所以当你打印时会发生GenMsg两个字符串打印.然后你打印DoneMsg并得到第二个"Done".
您需要在每个字符串后面添加一个值为0的字节:

GenMsg:     db "Generating move list file...",10,0
DoneMsg:    db "Done",10,0
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