Tob*_*ler 4 python directory-structure subdirectory
同样以GNU find的find . -type d -empty -delete我想找到空目录,包括那些(含emtpy子目录等和子目录)中的子目录,但不删除它们.是否有任何现有的解决方案或我必须手动使用os.walk(可能与topdown=False目前为止发现的空子目录有关并跟踪)?
这是一个使用生成器的简单解决方案os.walk:
import os
def find_empty_dirs(root_dir='.'):
for dirpath, dirs, files in os.walk(root_dir):
if not dirs and not files:
yield dirpath
print list(find_empty_dirs())
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我不明白为什么topdown=False有必要,我认为它没有改变任何东西.
这确实认为只包含空目录的目录本身不是空的,但那样做也是如此find . -type d -empty.
虽然,有一些更多的测试,我看find . -type d -empty -delete 不先删除空的子目录,再由上级目录,如果让他们空.但是使用os.walk不起作用,因为它在降序之前读取子目录列表,即使使用topdown=False.
删除空子目录树的递归解决方案可以是:
import os
def recursive_delete_if_empty(path):
"""Recursively delete empty directories; return True
if everything was deleted."""
if not os.path.isdir(path):
# If you also want to delete some files like desktop.ini, check
# for that here, and return True if you delete them.
return False
# Note that the list comprehension here is necessary, a
# generator expression would shortcut and we don't want that!
if all([recursive_delete_if_empty(os.path.join(path, filename))
for filename in os.listdir(path)]):
# Either there was nothing here or it was all deleted
os.rmdir(path)
return True
else:
return False
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好的,这是我使用的手动解决方案os.walk。is_empty当然可以修改该函数,例如排除隐藏文件,或者在我的示例中desktop.ini:
import os
def empty_dirs(root_dir='.', recursive=True):
empty_dirs = []
for root, dirs, files in os.walk(root_dir, topdown=False):
#print root, dirs, files
if recursive:
all_subs_empty = True # until proven otherwise
for sub in dirs:
full_sub = os.path.join(root, sub)
if full_sub not in empty_dirs:
#print full_sub, "not empty"
all_subs_empty = False
break
else:
all_subs_empty = (len(dirs) == 0)
if all_subs_empty and is_empty(files):
empty_dirs.append(root)
yield root
def is_empty(files):
return (len(files) == 0 or files == ['desktop.ini'])
def find_empty_dirs(root_dir='.', recursive=True):
return list(empty_dirs(root_dir, recursive))
print find_empty_dirs(recursive=False)
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