ggplot2馅饼和甜甜圈图表在同一个地块上

Tav*_*avi 30 r ggplot2 pie-chart donut-chart

我想复制这个 在此输入图像描述与R ggplot.我有完全相同的数据:

browsers<-structure(list(browser = structure(c(3L, 3L, 3L, 3L, 2L, 2L, 
2L, 1L, 5L, 5L, 4L), .Label = c("Chrome", "Firefox", "MSIE", 
"Opera", "Safari"), class = "factor"), version = structure(c(5L, 
6L, 7L, 8L, 2L, 3L, 4L, 1L, 10L, 11L, 9L), .Label = c("Chrome 10.0", 
"Firefox 3.5", "Firefox 3.6", "Firefox 4.0", "MSIE 6.0", "MSIE 7.0", 
"MSIE 8.0", "MSIE 9.0", "Opera 11.x", "Safari 4.0", "Safari 5.0"
), class = "factor"), share = c(10.85, 7.35, 33.06, 2.81, 1.58, 
13.12, 5.43, 9.91, 1.42, 4.55, 1.65), ymax = c(10.85, 18.2, 51.26, 
54.07, 55.65, 68.77, 74.2, 84.11, 85.53, 90.08, 91.73), ymin = c(0, 
10.85, 18.2, 51.26, 54.07, 55.65, 68.77, 74.2, 84.11, 85.53, 
90.08)), .Names = c("browser", "version", "share", "ymax", "ymin"
), row.names = c(NA, -11L), class = "data.frame")
Run Code Online (Sandbox Code Playgroud)

它看起来像这样:

> browsers
   browser      version  share   ymax   ymin
1     MSIE     MSIE 6.0  10.85  10.85   0.00
2     MSIE     MSIE 7.0   7.35  18.20  10.85
3     MSIE     MSIE 8.0  33.06  51.26  18.20
4     MSIE     MSIE 9.0   2.81  54.07  51.26
5  Firefox  Firefox 3.5   1.58  55.65  54.07
6  Firefox  Firefox 3.6  13.12  68.77  55.65
7  Firefox  Firefox 4.0   5.43  74.20  68.77
8   Chrome  Chrome 10.0   9.91  84.11  74.20
9   Safari   Safari 4.0   1.42  85.53  84.11
10  Safari   Safari 5.0   4.55  90.08  85.53
11   Opera   Opera 11.x   1.65  91.73  90.08
Run Code Online (Sandbox Code Playgroud)

到目前为止,我已经绘制了各个组件(即版本的圆环图和浏览器的饼图),如下所示:

ggplot(browsers) + geom_rect(aes(fill=version, ymax=ymax, ymin=ymin, xmax=4, xmin=3)) +
coord_polar(theta="y") + xlim(c(0, 4))
Run Code Online (Sandbox Code Playgroud)

在此输入图像描述

ggplot(browsers) + geom_bar(aes(x = factor(1), fill = browser),width = 1) +
coord_polar(theta="y")
Run Code Online (Sandbox Code Playgroud)

在此输入图像描述

问题是,如何将两者结合起来看起来像最顶层的图像?我尝试了很多方法,例如:

ggplot(browsers) + geom_rect(aes(fill=version, ymax=ymax, ymin=ymin, xmax=4, xmin=3)) +         geom_bar(aes(x = factor(1), fill = browser),width = 1) + coord_polar(theta="y") + xlim(c(0, 4)) 
Run Code Online (Sandbox Code Playgroud)

但我的所有结果都是扭曲的或以错误消息结束.

raw*_*awr 32

编辑2

我原来的答案真是愚蠢.这是一个更短的版本,它使用更简单的界面完成大部分工作.

#' x      numeric vector for each slice
#' group  vector identifying the group for each slice
#' labels vector of labels for individual slices
#' col    colors for each group
#' radius radius for inner and outer pie (usually in [0,1])

donuts <- function(x, group = 1, labels = NA, col = NULL, radius = c(.7, 1)) {
  group <- rep_len(group, length(x))
  ug  <- unique(group)
  tbl <- table(group)[order(ug)]

  col <- if (is.null(col))
    seq_along(ug) else rep_len(col, length(ug))
  col.main <- Map(rep, col[seq_along(tbl)], tbl)
  col.sub  <- lapply(col.main, function(x) {
    al <- head(seq(0, 1, length.out = length(x) + 2L)[-1L], -1L)
    Vectorize(adjustcolor)(x, alpha.f = al)
  })

  plot.new()

  par(new = TRUE)
  pie(x, border = NA, radius = radius[2L],
      col = unlist(col.sub), labels = labels)

  par(new = TRUE)
  pie(x, border = NA, radius = radius[1L],
      col = unlist(col.main), labels = NA)
}

par(mfrow = c(1,2), mar = c(0,4,0,4))
with(browsers,
     donuts(share, browser, sprintf('%s: %s%%', version, share),
            col = c('cyan2','red','orange','green','dodgerblue2'))
)

with(mtcars,
     donuts(mpg, interaction(gear, cyl), rownames(mtcars))
)
Run Code Online (Sandbox Code Playgroud)

在此输入图像描述


原帖

你们没有givemedonutsorgivemedeath功能吗?基本图形始终是这种非常详细的方式.但是想不出一个优雅的方式来绘制中心派标签.

givemedonutsorgivemedeath('~/desktop/donuts.pdf') 
Run Code Online (Sandbox Code Playgroud)

给我

在此输入图像描述

请注意,在?pie你看来

Pie charts are a very bad way of displaying information.
Run Code Online (Sandbox Code Playgroud)

码:

browsers <- structure(list(browser = structure(c(3L, 3L, 3L, 3L, 2L, 2L, 
  2L, 1L, 5L, 5L, 4L), .Label = c("Chrome", "Firefox", "MSIE", 
  "Opera", "Safari"), class = "factor"), version = structure(c(5L, 
  6L, 7L, 8L, 2L, 3L, 4L, 1L, 10L, 11L, 9L), .Label = c("Chrome 10.0", 
  "Firefox 3.5", "Firefox 3.6", "Firefox 4.0", "MSIE 6.0", "MSIE 7.0", 
  "MSIE 8.0", "MSIE 9.0", "Opera 11.x", "Safari 4.0", "Safari 5.0"), 
  class = "factor"), share = c(10.85, 7.35, 33.06, 2.81, 1.58, 
  13.12, 5.43, 9.91, 1.42, 4.55, 1.65), ymax = c(10.85, 18.2, 51.26, 
  54.07, 55.65, 68.77, 74.2, 84.11, 85.53, 90.08, 91.73), ymin = c(0, 
  10.85, 18.2, 51.26, 54.07, 55.65, 68.77, 74.2, 84.11, 85.53, 
  90.08)), .Names = c("browser", "version", "share", "ymax", "ymin"),
  row.names = c(NA, -11L), class = "data.frame")

browsers$total <- with(browsers, ave(share, browser, FUN = sum))

givemedonutsorgivemedeath <- function(file, width = 15, height = 11) {
  ## house keeping 
  if (missing(file)) file <- getwd()
  plot.new(); op <- par(no.readonly = TRUE); on.exit(par(op))

  pdf(file, width = width, height = height, bg = 'snow')

  ## useful values and colors to work with
  ## each group will have a specific color
  ## each subgroup will have a specific shade of that color
  nr <- nrow(browsers)
  width <- max(sqrt(browsers$share)) / 0.8

  tbl <- with(browsers, table(browser)[order(unique(browser))])
  cols <- c('cyan2','red','orange','green','dodgerblue2')
  cols <- unlist(Map(rep, cols, tbl))

  ## loop creates pie slices
  plot.new()
  par(omi = c(0.5,0.5,0.75,0.5), mai = c(0.1,0.1,0.1,0.1), las = 1)
  for (i in 1:nr) {
    par(new = TRUE)

    ## create color/shades
    rgb <- col2rgb(cols[i])
    f0 <- rep(NA, nr)
    f0[i] <- rgb(rgb[1], rgb[2], rgb[3], 190 / sequence(tbl)[i], maxColorValue = 255)

    ## stick labels on the outermost section
    lab <- with(browsers, sprintf('%s: %s', version, share))
    if (with(browsers, share[i] == max(share))) {
      lab0 <- lab
    } else lab0 <- NA

    ## plot the outside pie and shades of subgroups
    pie(browsers$share, border = NA, radius = 5 / width, col = f0, 
        labels = lab0, cex = 1.8)

    ## repeat above for the main groups
    par(new = TRUE)
    rgb <- col2rgb(cols[i])
    f0[i] <- rgb(rgb[1], rgb[2], rgb[3], maxColorValue = 255)

    pie(browsers$share, border = NA, radius = 4 / width, col = f0, labels = NA)
  }

  ## extra labels on graph

  ## center labels, guess and check?
  text(x = c(-.05, -.05, 0.15, .25, .3), y = c(.08, -.12, -.15, -.08, -.02), 
       labels = unique(browsers$browser), col = 'white', cex = 1.2)

  mtext('Browser market share, April 2011', side = 3, line = -1, adj = 0, 
        cex = 3.5, outer = TRUE)
  mtext('stackoverflow.com:::maryam', side = 3, line = -3.6, adj = 0,
        cex = 1.75, outer = TRUE, font = 3)
  mtext('/questions/26748069/ggplot2-pie-and-donut-chart-on-same-plot',
        side = 1, line = 0, adj = 1.0, cex = 1.2, outer = TRUE, font = 3)
  dev.off()
}

givemedonutsorgivemedeath('~/desktop/donuts.pdf')
Run Code Online (Sandbox Code Playgroud)

编辑1

width <- 5

tbl <- table(browsers$browser)[order(unique(browsers$browser))]
col.main <- Map(rep, seq_along(tbl), tbl)
col.sub  <- lapply(col.main, function(x)
  Vectorize(adjustcolor)(x, alpha.f = seq_along(x) / length(x)))

plot.new()

par(new = TRUE)
pie(browsers$share, border = NA, radius = 5 / width,
    col = unlist(col.sub), labels = browsers$version)

par(new = TRUE)
pie(browsers$share, border = NA, radius = 4 / width,
    col = unlist(col.main), labels = NA)
Run Code Online (Sandbox Code Playgroud)

  • @ user890739添加了一个看起来相当普遍的功能,让我知道这是否更好,谢谢你的点击 (2认同)

use*_*377 22

我发现首先在直角坐标上工作更容易,当这是正确的,然后切换到极坐标.x坐标变为极坐标的半径.因此,在直角坐标中,内部图从零到数字,如3,外带从3到4.

例如

ggplot(browsers) + 
  geom_rect(aes(fill=version, ymax=ymax, ymin=ymin, xmax=4, xmin=3)) +
  geom_rect(aes(fill=browser, ymax=ymax, ymin=ymin, xmax=3, xmin=0)) +
  xlim(c(0, 4)) + 
  theme(aspect.ratio=1) 
Run Code Online (Sandbox Code Playgroud)

在此输入图像描述

然后,当你切换到极地时,你会得到类似你想要的东西.

ggplot(browsers) + 
  geom_rect(aes(fill=version, ymax=ymax, ymin=ymin, xmax=4, xmin=3)) +
  geom_rect(aes(fill=browser, ymax=ymax, ymin=ymin, xmax=3, xmin=0)) +
  xlim(c(0, 4)) + 
  theme(aspect.ratio=1) +
  coord_polar(theta="y")  
Run Code Online (Sandbox Code Playgroud)

在此输入图像描述

这是一个开始,但可能需要微调对y(或角度)的依赖性,并且还要计算标签/图例/着色...通过对内圈和外圈使用rect,这应该简化调整着色.此外,使用reshape2 :: melt函数重新组织数据以便通过使用组(或颜色)使图例变得正确是有用的.

  • 有关此想法的更多信息,请参见http://vita.had.co.nz/papers/prodplots.html (3认同)

小智 7

我创建了一个通用的甜甜圈绘图功能,可以做到这一点

  • 绘制环形图,即绘制饼图,panel并按给定的百分比pctr和列来着色每个圆形扇区colors.环宽度可通过被调谐outradius> radius> innerradius.
  • 将几个环形图叠加在一起.

主要功能实际绘制条形图并将其弯曲成环形,因此它是饼图和条形图之间的东西.

饼图示例,两个环:

馅饼1

浏览器饼图

馅饼2

donuts_plot <- function(
                        panel = runif(3), # counts
                        pctr = c(.5,.2,.9), # percentage in count
                        legend.label='',
                        cols = c('chartreuse', 'chocolate','deepskyblue'), # colors
                        outradius = 1, # outter radius
                        radius = .7,   # 1-width of the donus 
                        add = F,
                        innerradius = .5, # innerradius, if innerradius==innerradius then no suggest line
                        legend = F,
                        pilabels=F,
                        legend_offset=.25, # non-negative number, legend right position control
                        borderlit=c(T,F,T,T)
                        ){
    par(new=add)
    if(sum(legend.label=='')>=1) legend.label=paste("Series",1:length(pctr))
    if(pilabels){
        pie(panel, col=cols,border = borderlit[1],labels = legend.label,radius = outradius)
    }
    panel = panel/sum(panel)

    pctr2= panel*(1 - pctr)
    pctr3 = c(pctr,pctr)
    pctr_indx=2*(1:length(pctr))
    pctr3[pctr_indx]=pctr2
    pctr3[-pctr_indx]=panel*pctr
    cols_fill = c(cols,cols)
    cols_fill[pctr_indx]='white'
    cols_fill[-pctr_indx]=cols
    par(new=TRUE)
    pie(pctr3, col=cols_fill,border = borderlit[2],labels = '',radius = outradius)
    par(new=TRUE)
    pie(panel, col='white',border = borderlit[3],labels = '',radius = radius)
    par(new=TRUE)
    pie(1, col='white',border = borderlit[4],labels = '',radius = innerradius)
    if(legend){
        # par(mar=c(5.2, 4.1, 4.1, 8.2), xpd=TRUE)
        legend("topright",inset=c(-legend_offset,0),legend=legend.label, pch=rep(15,'.',length(pctr)), 
               col=cols,bty='n')
    }
    par(new=FALSE)
}
## col- > subcor(change hue/alpha)
subcolors <- function(.dta,main,mainCol){
    tmp_dta = cbind(.dta,1,'col')
    tmp1 = unique(.dta[[main]])
    for (i in 1:length(tmp1)){
        tmp_dta$"col"[.dta[[main]] == tmp1[i]] = mainCol[i]
    }
    u <- unlist(by(tmp_dta$"1",tmp_dta[[main]],cumsum))
    n <- dim(.dta)[1]
    subcol=rep(rgb(0,0,0),n);
    for(i in 1:n){
        t1 = col2rgb(tmp_dta$col[i])/256
        subcol[i]=rgb(t1[1],t1[2],t1[3],1/(1+u[i]))
    }
    return(subcol);
}
### Then get the plot is fairly easy:
# INPUT data
browsers <- structure(list(browser = structure(c(3L, 3L, 3L, 3L, 2L, 2L, 
                                                 2L, 1L, 5L, 5L, 4L), 
                                               .Label = c("Chrome", "Firefox", "MSIE","Opera", "Safari"),class = "factor"), 
                           version = structure(c(5L,6L, 7L, 8L, 2L, 3L, 4L, 1L, 10L, 11L, 9L), 
                                               .Label = c("Chrome 10.0", "Firefox 3.5", "Firefox 3.6", "Firefox 4.0", "MSIE 6.0", 
                                                          "MSIE 7.0","MSIE 8.0", "MSIE 9.0", "Opera 11.x", "Safari 4.0", "Safari 5.0"),
                                               class = "factor"), 
                           share = c(10.85, 7.35, 33.06, 2.81, 1.58,13.12, 5.43, 9.91, 1.42, 4.55, 1.65), 
                           ymax = c(10.85, 18.2, 51.26,54.07, 55.65, 68.77, 74.2, 84.11, 85.53, 90.08, 91.73), 
                           ymin = c(0,10.85, 18.2, 51.26, 54.07, 55.65, 68.77, 74.2, 84.11, 85.53,90.08)),
                      .Names = c("browser", "version", "share", "ymax", "ymin"),
                      row.names = c(NA, -11L), class = "data.frame")
## data clean
browsers=browsers[order(browsers$browser,browsers$share),]
arr=aggregate(share~browser,browsers,sum)
### choose your cols
mainCol =  c('chartreuse3', 'chocolate3','deepskyblue3','gold3','deeppink3')
donuts_plot(browsers$share,rep(1,11),browsers$version,
        cols=subcolors(browsers,"browser",mainCol),
        legend=F,pilabels = T,borderlit = rep(F,4) )
donuts_plot(arr$share,rep(1,5),arr$browser,
        cols=mainCol,pilabels=F,legend=T,legend_offset=-.02,
        outradius = .71,radius = .0,innerradius=.0,add=T,
        borderlit = rep(F,4) )
###end of line
Run Code Online (Sandbox Code Playgroud)


did*_*dac 5

你可以使用包 ggsunburst 得到类似的东西

# using your data without "ymax" and "ymin"
browsers <- structure(list(browser = structure(c(3L, 3L, 3L, 3L, 2L, 2L,
2L, 1L, 5L, 5L, 4L), .Label = c("Chrome", "Firefox", "MSIE",
"Opera", "Safari"), class = "factor"), version = structure(c(5L,
6L, 7L, 8L, 2L, 3L, 4L, 1L, 10L, 11L, 9L), .Label = c("Chrome 10.0",
"Firefox 3.5", "Firefox 3.6", "Firefox 4.0", "MSIE 6.0", "MSIE 7.0",
"MSIE 8.0", "MSIE 9.0", "Opera 11.x", "Safari 4.0", "Safari 5.0"
), class = "factor"), share = c(10.85, 7.35, 33.06, 2.81, 1.58,
13.12, 5.43, 9.91, 1.42, 4.55, 1.65)), .Names = c("parent", "node", "size")
, row.names = c(NA, -11L), class = "data.frame")

# add column browser to be used for colouring
browsers$browser <- browsers$parent

# write data.frame into csv file
write.table(browsers, file = 'browsers.csv', row.names = F, sep = ",")

# install ggsunburst
if (!require("ggplot2")) install.packages("ggplot2")
if (!require("rPython")) install.packages("rPython")
install.packages("http://genome.crg.es/~didac/ggsunburst/ggsunburst_0.0.9.tar.gz", repos=NULL, type="source")
library(ggsunburst)

# generate data structure
sb <- sunburst_data('browsers.csv', type = 'node_parent', sep = ",", node_attributes = c("browser","size"))

# add name as browser attribute for colouring to internal nodes
sb$rects[!sb$rects$leaf,]$browser <- sb$rects[!sb$rects$leaf,]$name

# plot adding geom_text layer for showing the "size" value
p <- sunburst(sb, rects.fill.aes = "browser", node_labels = T, node_labels.min = 15)
p + geom_text(data = sb$leaf_labels,
    aes(x=x, y=0.1, label=paste(size,"%"), angle=angle, hjust=hjust), size = 2)
Run Code Online (Sandbox Code Playgroud)

在此处输入图片说明


小智 5

PieDonut()您可以使用包中的函数仅使用一行代码来创建如下所示的饼图webr

# loadin the libraries
library(ggplot2)
library(webr)

# replicating the table
browsers<-structure(
  list(browser = structure(c(3L, 3L, 3L, 3L, 2L, 2L, 2L, 1L, 5L, 5L, 4L),
                           .Label = c("Chrome", "Firefox", "MSIE", "Opera", "Safari"), class = "factor"), 
       version = structure(c(5L, 6L, 7L, 8L, 2L, 3L, 4L, 1L, 10L, 11L, 9L), 
                           .Label = c("Chrome 10.0", "Firefox 3.5", "Firefox 3.6", "Firefox 4.0", "MSIE 6.0", "MSIE 7.0", "MSIE 8.0", "MSIE 9.0", "Opera 11.x", "Safari 4.0", "Safari 5.0"), class = "factor"), 
       share = c(10.85, 7.35, 33.06, 2.81, 1.58, 13.12, 5.43, 9.91, 1.42, 4.55, 1.65), 
       ymax = c(10.85, 18.2, 51.26, 54.07, 55.65, 68.77, 74.2, 84.11, 85.53, 90.08, 91.73), 
       ymin = c(0, 10.85, 18.2, 51.26, 54.07, 55.65, 68.77, 74.2, 84.11, 85.53, 90.08)), 
  .Names = c("browser", "version", "share", "ymax", "ymin"), row.names = c(NA, -11L), class = "data.frame")

# building the pie-donut chart
PieDonut(browsers, aes(browser, version, count=share),
         title = "Browser market share, April, 2011",
         ratioByGroup = FALSE)
Run Code Online (Sandbox Code Playgroud)