use*_*r93 9 python random timestamp
有没有办法在Python中以严格增加的格式创建随机不规则时间戳列表?例如:
20/09/2013 13:00
20/09/2013 13:01
20/09/2013 13:05
20/09/2013 13:09
20/09/2013 13:16
20/09/2013 13:26
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小智 12
您可以构建一个随机生成器.
你可以生成randrange(60)
0-60(分钟)之间的radom数
用于timedelta
为实际日期添加时间,在您的情况下,它是20/09/2013 13:..
构建一个生成器random_date
,具有开始日期和您想要生成的日期数.
Run Code Online (Sandbox Code Playgroud)from random import randrange import datetime def random_date(start,l): current = start while l >= 0: curr = current + datetime.timedelta(minutes=randrange(60)) yield curr l-=1 startDate = datetime.datetime(2013, 9, 20,13,00) for x in random_date(startDate,10): print x.strftime("%d/%m/%y %H:%M")
输出:
20/09/13 13:12
20/09/13 13:02
20/09/13 13:50
20/09/13 13:13
20/09/13 13:56
20/09/13 13:40
20/09/13 13:10
20/09/13 13:35
20/09/13 13:37
20/09/13 13:45
20/09/13 13:27
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UPDATE
您可以通过将差异编号添加到您生成的最后日期来欺骗它,然后反转整体列表.您还可以更改每次添加的随机数,以获得所需的结果.
你的代码看起来像.
from random import randrange
import datetime
def random_date(start,l):
current = start
while l >= 0:
current = current + datetime.timedelta(minutes=randrange(10))
yield current
l-=1
startDate = datetime.datetime(2013, 9, 20,13,00)
for x in reversed(list(random_date(startDate,10))):
print x.strftime("%d/%m/%y %H:%M")
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输出:
20/09/13 13:45
20/09/13 13:36
20/09/13 13:29
20/09/13 13:25
20/09/13 13:20
20/09/13 13:19
20/09/13 13:16
20/09/13 13:16
20/09/13 13:07
20/09/13 13:03
20/09/13 13:01
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