Cha*_*les 2 sql t-sql sql-server
我有一张桌子
| Location | Unit | ...
+----------|------+----
| A | 1 | ...
| A | 1 | ...
| B | 1 | ...
| A | 2 | ...
| C | 2 | ...
| ... | ... | ...
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我希望计算一个新表,其中包含每个单元的"平均"位置值,具体如下:
| Location | Unit | Weight |
+----------|------+--------+
| A | 1 | 0.6667 |
| B | 1 | 0.3333 |
| A | 2 | 0.5 |
| C | 2 | 0.5 |
| ... | ... | ... |
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当然,获得总数很简单
select unit, location, count(*)
from table1
group by unit, location;
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并创建表
create table table2 (Unit nvarchar(50), Location int, Weight float);
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但我不确定如何用平均数据填充它.(这并不难,但不知怎的,我被卡住了......自从我在SQL Server上工作已经很多年了.)
你会用到COUNT OVER这个:
select distinct
location, unit,
cast(count(*) over (partition by unit, location) as decimal) /
cast(count(*) over (partition by unit) as decimal) as weight
from mytable
order by unit, location;
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