lin*_*luk 4 delphi canvas bitmap alpha-transparency delphi-xe5
我想在不透明的画布上绘制位图,其中位图具有透明色.
但我无法结合它.如果我合并它,则忽略不透明度.
这是我写的代码:
procedure TForm1.FormPaint(Sender: TObject);
var b1,b2:TBitmap;
begin
// Example how it opacity works:
b1 := TBitmap.Create;
b1.SetSize(20,20);
b1.Canvas.Brush.Color := clBlue;
b1.Canvas.Rectangle(0,0,20,20);
Canvas.Draw(10,10,b1,$ff); // Works
Canvas.Draw(40,10,b1,$66); // Works
// I need it in combination with TransparentColor:
b2 := TBitmap.Create;
// next 3 lines are different from above
b2.Transparent := true;
b2.TransparentColor := clFuchsia;
b2.Canvas.Brush.Color := clFuchsia;
b2.SetSize(20,20);
b2.Canvas.Brush.Color := clBlue;
b2.Canvas.Ellipse(0,0,20,20);
Canvas.Draw(10,40,b2,$ff); // Works (full opacity)
Canvas.Draw(40,40,b2,$66); // Ignores the $66 Opacity
b1.Free;
b2.Free;
end;
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我怎么能用透明背景绘制(一个蓝色的圆圈),只有40%的不透明度?
如果可能的话,我会优先选择没有直接winapi的解决方案(如bitblt,...).
我尝试了几个hacks,比如将alpha通道转换为TColor值,但它不起作用.
在这里我尝试了什么:
procedure TForm1.FormPaint(Sender: TObject);
var b:TBitmap;
begin
b := TBitmap.Create;
b.PixelFormat := pf32bit;
b.AlphaFormat := afDefined;
b.Canvas.Brush.Color := 0 and ($ff shl 32); // Background Transperency
b.SetSize(20,20);
b.Canvas.Brush.Color := clBlue + (($ff-$66) shl 32);
b.Canvas.Ellipse(0,0,20,20);
Canvas.Draw(10,10,b);
b.Free;
end;
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提前致谢!
编辑:我的系统:windows 7 64bit上的delphi xe 5(但使用32位编译器)
可以procedure TBitmap.DrawTransparent
在单位图形中看到发生的情况.
如果图像的属性设置为透明,如示例中的b2所示,将Graphics.TransparentStretchBlt
使用StretchBlt
不同的蒙版绘制位图
以绘制图像,并且无法使用Alpha通道.不透明的位图,你的b1,将使用AlphaBlend绘制
.
要达到目标,您可以使用另一个位图b2,将Alphachannel设置为0,在b3上使用不透明度$ 66绘制b2,将每个像素的Alphachannel设置为255,这是b2中的clFuchsia,然后使用所需的不透明度绘制此位图
type
pRGBQuadArray = ^TRGBQuadArray;
TRGBQuadArray = ARRAY [0 .. 0] OF TRGBQuad;
TRefChanel=(rcBlue,rcRed,rcGreen);
procedure SetBitmapAlpha(ABitmap: TBitMap; Alpha: Byte);
var
pscanLine32: pRGBQuadArray;
nScanLineCount, nPixelCount : Integer;
begin
with ABitmap do
begin
PixelFormat := pf32Bit;
HandleType := bmDIB;
ignorepalette := true;
alphaformat := afDefined;
for nScanLineCount := 0 to Height - 1 do
begin
pscanLine32 := Scanline[nScanLineCount];
for nPixelCount := 0 to Width - 1 do
with pscanLine32[nPixelCount] do
begin
rgbReserved := Alpha;
end;
end;
end;
end;
procedure AdaptBitmapAlpha(ABitmap,TranspBitmap:TBitmap);
var
pscanLine32,pscanLine32_2: pRGBQuadArray;
nScanLineCount, nPixelCount : Integer;
begin
with ABitmap do
begin
PixelFormat := pf32Bit;
HandleType := bmDIB;
ignorepalette := true;
alphaformat := afDefined;
for nScanLineCount := 0 to Height - 1 do
begin
pscanLine32 := Scanline[nScanLineCount];
pscanLine32_2 := TranspBitmap.Scanline[nScanLineCount];
for nPixelCount := 0 to Width - 1 do
with pscanLine32[nPixelCount] do
begin
// all picels with are not clFuchsia in the transparent bitmap
if NOT ((pscanLine32_2[nPixelCount].rgbBlue=255) AND (pscanLine32_2[nPixelCount].rgbRed=255) AND (pscanLine32_2[nPixelCount].rgbGreen=0) ) then
begin
rgbReserved := 255;
end
else
begin
rgbBlue := 0;
rgbRed := 0;
rgbGreen := 0;
end;
end;
end;
end;
end;
procedure TAForm.FormPaint(Sender: TObject);
var b1,b2,b3:TBitmap;
BF: TBlendFunction;
begin
// Example how it opacity works:
b1 := TBitmap.Create;
b1.SetSize(20,20);
b1.Canvas.Brush.Color := clBlue;
b1.Canvas.Rectangle(0,0,20,20);
Canvas.Draw(10,10,b1,$ff); // Works
Canvas.Draw(40,10,b1,$66); // Works
// I need it in combination with TransparentColor:
b3 := TBitmap.Create;
b3.PixelFormat := pf32Bit;
b2 := TBitmap.Create;
b2.PixelFormat := pf32Bit;
// next 3 lines are different from above
b2.Transparent := true;
b2.TransparentColor := clFuchsia;
b2.Canvas.Brush.Color := clFuchsia;
b2.SetSize(20,20);
b2.Canvas.Brush.Color := clBlue;
b2.Canvas.Ellipse(0,0,20,20);
Canvas.Draw(10,40,b2,$ff); // Works (full opacity)
b3.SetSize(20,20);
SetBitmapAlpha(b3,0);
b3.Canvas.Draw(0,0,b2,$66);
AdaptBitmapAlpha(b3,b2);
Canvas.Draw(40,40,b3,$66);
b1.Free;
b2.Free;
b3.Free;
end;
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