cae*_*lin 7 php verification hash password-encryption
我通过password_hash哈希插入的密码.我使用password_verify验证它们.
但是,当我在我的数据库中插入哈希密码并尝试验证它时,两个输出总是彼此不同.
我的网页如下,
main_login.php(表格):
<?php include 'header.php';?>
<body>
<form role="form" method="post" action="login.php">
<div class="form-group">
<label for="usrname">Username:</label>
<input type="text" class="form-control" name="usrname" placeholder="Enter username">
</div>
<div class="form-group">
<label for="passwrd">Password:</label>
</div>
<input type="password" class="form-control" name="passwrd" placeholder="Enter password">
<br>
<input type="checkbox">Remember Me
<br>
<br>
<button type="submit" class="btn btn-default">Submit</button>
</form>
</body>
</html>
login.php(handler):
<?php
include 'vars.php';
include 'header.php';
$sql="SELECT * FROM members WHERE usrname='$usrname'";
$result=mysqli_query($con,$sql);
$count=mysqli_num_rows($result);
$row=mysqli_fetch_row($result);
$verify=password_verify($hash,$row[2]);
if($verify){
$_SESSION["usrname"]=$usrname;
echo "Correct";
}
else {
echo "user: " . $usrname. "<br>";
echo "pass: " . $hash. "<br>";
echo "db: " . $row[2]."<br>";
echo "Wrong Username or Password";
}
?>
vars.php:
<?php
$h='localhost';$u='caelin';$p='****';$d='ombouwnh';
$con=mysqli_connect($h,$u,$p,$d);
$usrname=$_POST['usrname'];
$passwrd=$_POST['passwrd'];
$hash=password_hash($passwrd, PASSWORD_DEFAULT);
?>
当我尝试使用用户名'caca'和密码'caca'登录时,每次重试时,我都会得到不同的输出.我在stackoverflow上找不到这个特殊问题.
TIA
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小智 13
该函数password_verify();有两个参数; 非散列输入,以及与之比较的存储散列.它会自动散列非散列输入,以将其与存储的版本进行比较.因此,您的初始代码重新散列了已经散列的密码.应该是这样的:
$verify=password_verify($_POST['passwrd'],$row[2]);
if($verify){
$_SESSION["usrname"]=$usrname;
echo "Correct";
}
else {
echo "user: " . $usrname. "<br>";
echo "pass: " . $hash. "<br>";
echo "db: " . $row[2]."<br>";
echo "Wrong Username or Password";
}