鉴于django民意调查教程中的以下模型:
class Question(models.Model):
question_text = models.CharField(max_length=200)
pub_date = models.DateTimeField('date published')
def __str__(self):
return self.question_text
def was_published_recently(self):
now = timezone.now()
return now - datetime.timedelta(days=1) <= self.pub_date <= now
was_published_recently.admin_order_field = 'pub_date'
was_published_recently.boolean = True
was_published_recently.short_description = 'Published recently'
class Choice(models.Model):
question = models.ForeignKey(Question)
choice_text = models.CharField(max_length=200)
votes = models.IntegerField(default=0)
def __str__(self):
return self.choice_text
Run Code Online (Sandbox Code Playgroud)
我想能够排除没有的问题和教程中建议的选择.我一直在玩Filter,但我无法理解,我试过:
def get_queryset(self):
return Question.objects.filter(pub_date__lte=timezone.now(), choice__count__gt=0)
Run Code Online (Sandbox Code Playgroud)
但我得到了
Relation fields do not support nested lookups
Run Code Online (Sandbox Code Playgroud)
如何根据没有任何选择的问题进行过滤?
你也可以使用如下
from django.db.models import Count
......
def get_queryset(self):
return Question.objects.annotate(num_choice=Count('choice')).filter(pub_date__lte=timezone.now(), num_choice=0)
Run Code Online (Sandbox Code Playgroud)