her*_*tao 77
如果内存Mat mat是连续的(其所有数据都是连续的),您可以直接将其数据转换为1D数组:
std::vector<uchar> array(mat.rows*mat.cols);
if (mat.isContinuous())
array = mat.data;
否则,您必须逐行获取其数据,例如,到2D数组:
uchar **array = new uchar*[mat.rows];
for (int i=0; i<mat.rows; ++i)
array[i] = new uchar[mat.cols];
for (int i=0; i<mat.rows; ++i)
array[i] = mat.ptr<uchar>(i);
更新:如果您正在使用它会更容易std::vector,您可以这样做:
std::vector<uchar> array;
if (mat.isContinuous()) {
// array.assign(mat.datastart, mat.dataend); // <- has problems for sub-matrix like mat = big_mat.row(i)
array.assign(mat.data, mat.data + mat.total());
} else {
for (int i = 0; i < mat.rows; ++i) {
array.insert(array.end(), mat.ptr<uchar>(i), mat.ptr<uchar>(i)+mat.cols);
}
}
ps:对于cv::Mat其他类型的s CV_32F,你应该这样做:
std::vector<float> array;
if (mat.isContinuous()) {
// array.assign((float*)mat.datastart, (float*)mat.dataend); // <- has problems for sub-matrix like mat = big_mat.row(i)
array.assign((float*)mat.data, (float*)mat.data + mat.total());
} else {
for (int i = 0; i < mat.rows; ++i) {
array.insert(array.end(), mat.ptr<float>(i), mat.ptr<float>(i)+mat.cols);
}
}
mrg*_*oom 12
这里是另一个可能的解决方案假设矩阵有一列(你可以通过重塑原来垫一列垫重塑):
Mat matrix= Mat::zeros(20, 1, CV_32FC1);
vector<float> vec;
matrix.col(0).copyTo(vec);
uchar * arr = image.isContinuous()? image.data: image.clone().data;
uint length = image.total()*image.channels();
cv::Mat flat = image.reshape(1, image.total()*image.channels());
std::vector<uchar> vec = image.isContinuous()? flat : flat.clone();
Both work for any general cv::Mat.
cv::Mat image;
image = cv::imread(argv[1], cv::IMREAD_UNCHANGED); // Read the file
cv::namedWindow("cvmat", cv::WINDOW_AUTOSIZE );// Create a window for display.
cv::imshow("cvmat", image ); // Show our image inside it.
// flatten the mat.
uint totalElements = image.total()*image.channels(); // Note: image.total() == rows*cols.
cv::Mat flat = image.reshape(1, totalElements); // 1xN mat of 1 channel, O(1) operation
if(!image.isContinuous()) {
flat = flat.clone(); // O(N),
}
// flat.data is your array pointer
auto * ptr = flat.data; // usually, its uchar*
// You have your array, its length is flat.total() [rows=1, cols=totalElements]
// Converting to vector
std::vector<uchar> vec(flat.data, flat.data + flat.total());
// Testing by reconstruction of cvMat
cv::Mat restored = cv::Mat(image.rows, image.cols, image.type(), ptr); // OR vec.data() instead of ptr
cv::namedWindow("reconstructed", cv::WINDOW_AUTOSIZE);
cv::imshow("reconstructed", restored);
cv::waitKey(0);
Mat is stored as a contiguous block of memory, if created using one of its constructors or when copied to another Mat using clone() or similar methods. To convert to an array or vector we need the address of its first block and array/vector length.
Mat::data is a public uchar pointer to its memory.
But this memory may not be contiguous. As explained in other answers, we can check if mat.data is pointing to contiguous memory or not using mat.isContinous(). Unless you need extreme efficiency, you can obtain a continuous version of the mat using mat.clone() in O(N) time. (N = number of elements from all channels). However, when dealing images read by cv::imread() we will rarely ever encounter a non-continous mat.
Q: Should be row*cols*channels right?
A: Not always. It can be rows*cols*x*y*channels.
Q: Should be equal to mat.total()?
A: True for single channel mat. But not for multi-channel mat
Length of the array/vector is slightly tricky because of poor documentation of OpenCV. We have Mat::size public member which stores only the dimensions of single Mat without channels. For RGB image, Mat.size = [rows, cols] and not [rows, cols, channels]. Mat.total() returns total elements in a single channel of the mat which is equal to product of values in mat.size. For RGB image, total() = rows*cols. Thus, for any general Mat, length of continuous memory block would be mat.total()*mat.channels().
Apart from array/vector we also need the original Mat's mat.size [array like] and mat.type() [int]. Then using one of the constructors that take data's pointer, we can obtain original Mat. The optional step argument is not required because our data pointer points to continuous memory. I used this method to pass Mat as Uint8Array between nodejs and C++. This avoided writing C++ bindings for cv::Mat with node-addon-api.
小智 5
此处提供的示例均不适用于一般情况，即 N 维矩阵。任何使用“行”的内容都假设只有列和行，4 维矩阵可能有更多。
下面是一些示例代码，将非连续 N 维矩阵复制到连续内存流中 - 然后将其转换回 Cv::Mat
#include <iostream>
#include <cstdint>
#include <cstring>
#include <opencv2/opencv.hpp>
int main(int argc, char**argv)
{
if ( argc != 2 )
{
std::cerr << "Usage: " << argv[0] << " <Image_Path>\n";
return -1;
}
cv::Mat origSource = cv::imread(argv[1],1);
if (!origSource.data) {
std::cerr << "Can't read image";
return -1;
}
// this will select a subsection of the original source image - WITHOUT copying the data
// (the header will point to a region of interest, adjusting data pointers and row step sizes)
cv::Mat sourceMat = origSource(cv::Range(origSource.size[0]/4,(3*origSource.size[0])/4),cv::Range(origSource.size[1]/4,(3*origSource.size[1])/4));
// correctly copy the contents of an N dimensional cv::Mat
// works just as fast as copying a 2D mat, but has much more difficult to read code :)
// see http://stackoverflow.com/questions/18882242/how-do-i-get-the-size-of-a-multi-dimensional-cvmat-mat-or-matnd
// copy this code in your own cvMat_To_Char_Array() function which really OpenCV should provide somehow...
// keep in mind that even Mat::clone() aligns each row at a 4 byte boundary, so uneven sized images always have stepgaps
size_t totalsize = sourceMat.step[sourceMat.dims-1];
const size_t rowsize = sourceMat.step[sourceMat.dims-1] * sourceMat.size[sourceMat.dims-1];
size_t coordinates[sourceMat.dims-1] = {0};
std::cout << "Image dimensions: ";
for (int t=0;t<sourceMat.dims;t++)
{
// calculate total size of multi dimensional matrix by multiplying dimensions
totalsize*=sourceMat.size[t];
std::cout << (t>0?" X ":"") << sourceMat.size[t];
}
// Allocate destination image buffer
uint8_t * imagebuffer = new uint8_t[totalsize];
size_t srcptr=0,dptr=0;
std::cout << std::endl;
std::cout << "One pixel in image has " << sourceMat.step[sourceMat.dims-1] << " bytes" <<std::endl;
std::cout << "Copying data in blocks of " << rowsize << " bytes" << std::endl ;
std::cout << "Total size is " << totalsize << " bytes" << std::endl;
while (dptr<totalsize) {
// we copy entire rows at once, so lowest iterator is always [dims-2]
// this is legal since OpenCV does not use 1 dimensional matrices internally (a 1D matrix is a 2d matrix with only 1 row)
std::memcpy(&imagebuffer[dptr],&(((uint8_t*)sourceMat.data)[srcptr]),rowsize);
// destination matrix has no gaps so rows follow each other directly
dptr += rowsize;
// src matrix can have gaps so we need to calculate the address of the start of the next row the hard way
// see *brief* text in opencv2/core/mat.hpp for address calculation
coordinates[sourceMat.dims-2]++;
srcptr = 0;
for (int t=sourceMat.dims-2;t>=0;t--) {
if (coordinates[t]>=sourceMat.size[t]) {
if (t==0) break;
coordinates[t]=0;
coordinates[t-1]++;
}
srcptr += sourceMat.step[t]*coordinates[t];
}
}
// this constructor assumes that imagebuffer is gap-less (if not, a complete array of step sizes must be given, too)
cv::Mat destination=cv::Mat(sourceMat.dims, sourceMat.size, sourceMat.type(), (void*)imagebuffer);
// and just to proof that sourceImage points to the same memory as origSource, we strike it through
cv::line(sourceMat,cv::Point(0,0),cv::Point(sourceMat.size[1],sourceMat.size[0]),CV_RGB(255,0,0),3);
cv::imshow("original image",origSource);
cv::imshow("partial image",sourceMat);
cv::imshow("copied image",destination);
while (cv::waitKey(60)!='q');
}