cin*_*122 5 postgresql postgis
同样,我有一个在本地运行良好的函数,但将它移到网上会产生一个很大的错误......从有人指出我传递的参数数量不准确的回应中得到提示,我加倍 -在这种情况下检查以确保我将 5 个参数传递给函数本身......
Query failed: ERROR: operator does not exist: point <@> point HINT: No operator matches the given name and argument type(s). You may need to add explicit type casts.
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查询是这样的:
BEGIN; SELECT zip_proximity_sum('zc',
(SELECT g.lat FROM geocoded g
LEFT JOIN masterfile m ON g.recordid = m.id
WHERE m.zip = '10050' ORDER BY m.id LIMIT 1),
(SELECT g.lon FROM geocoded g
LEFT JOIN masterfile m ON g.recordid = m.id
WHERE m.zip = '10050' ORDER BY m.id LIMIT 1),
(SELECT m.zip FROM geocoded g
LEFT JOIN masterfile m ON g.recordid = m.id
WHERE m.zip = '10050' ORDER BY m.id LIMIT 1)
,10);
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PG 函数是这样的:
CREATE OR REPLACE FUNCTION zip_proximity_sum(refcursor, numeric, numeric, character, numeric)
RETURNS refcursor AS
$BODY$
BEGIN
OPEN $1 FOR
SELECT r.zip, point($2,$3) <@> point(g.lat, g.lon) AS distance
FROM
geocoded g LEFT JOIN masterfile r ON g.recordid = r.id
WHERE (geo_distance( point($2,$3),point(g.lat,g.lon)) < $5)
ORDER BY r.zip, distance;
RETURN $1;
END;
$BODY$
LANGUAGE 'plpgsql' VOLATILE
COST 100;
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以下是确切的命令:
create extension cube;
create extension earthdistance;
select (point(-0.1277,51.5073) <@> point(-74.006,40.7144)) as distance;
distance
------------------
3461.10547602474
(1 row)
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请注意,这points
是使用LONGITUDE FIRST创建的。根据文档:
点被视为(经度,纬度),反之亦然,因为经度更接近于 x 轴和纬度到 y 轴的直观想法。
这是可怕的设计......但它就是这样。
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